大致题意: 给出一个多边形,问你有多少种放法可以使得多边形稳定得立在平面上. 先对多边形求重心,在求凸包,枚举凸包的边,如果重心没有在边的范围内,则不行 判断是否在范围内可用点积来判断 #include<cstdio> #include<iostream> #include<cstring> #include<algorithm> #include<queue> #include<set> #include<map> #i…

F - Rotational Painting Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 3685 Appoint description:  System Crawler  (2014-11-09) Description Josh Lyman is a gifted painter. One of his great works…

Problem Description Josh Lyman is a gifted painter. One of his great works is a glass painting. He creates some well-designed lines on one side of a thick and polygonal glass, and renders it by some special dyes. The most fantastic thing is that it c…

链接 模板题已不叫题.. 三维凸包+凸包重心+点到平面距离(体积/点积)  体积-->混合积(先点乘再叉乘) #include <iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<stdlib.h> #include<vector> #include<cmath> #include<queue> #inclu…

把每个三角形看成一个质点,坐标就是各自的重心, #include<map> #include<set> #include<cmath> #include<queue> #include<stack> #include<vector> #include<cstdio> #include<cassert> #include<iomanip> #include<cstdlib> #includ…

Rotational Painting Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2498    Accepted Submission(s): 702 Problem Description Josh Lyman is a gifted painter. One of his great works is a glass pain…

新模板 /* HDU 4273 Rescue 给一个三维凸包,求重心到表面的最短距离 模板题:三维凸包+多边形重心+点面距离 */ #include<stdio.h> #include<algorithm> #include<string.h> #include<math.h> #include<stdlib.h> using namespace std; ; ; struct Point { double x,y,z; Point(){} Po…

也是用模板直接套的题目诶 //#pragma comment(linker, "/STACK:16777216") //for c++ Compiler #include <stdio.h> #include <iostream> #include <cstring> #include <cmath> #include <stack> #include <queue> #include <vector>…

POJ3528 HDU3662 第一道题 给定若干点 求凸包的表面积,第二题 给定若干点就凸包的面数. 简单说一下三维凸包的求法,首先对于4个点假设不共面,确定了唯一四面体,对于一个新的点,若它不在四面体内,为了让它进入凸包, 则对于所有凸包上的边,若边的一面是该点可以看到的而另一面看不到,则该点与该边构成的面要加入凸包. 模板代码非常清晰, #include<stdio.h> #include<algorithm> #include<string.h> #includ…

题意:给两个凸包,凸包能旋转,求凸包重心之间的最短距离. 思路:显然两个凸包贴在一起时,距离最短.所以,先求重心,再求重心到各个面的最短距离. 三维凸包+重心求法 重心求法:在凸包内,任意枚举一点,在与凸包其他一个面组成一个三棱锥.求出每个三棱锥的重心,把三棱锥等效成一个个质点,再求整体的重心. #include<cstdio> #include<cmath> #include<cstdlib> #include<cstring> #include<q…