Lintcode: Remove Node in Binary Search Tree】的更多相关文章

iven a root of Binary Search Tree with unique value for each node. Remove the node with given value. If there is no such a node with given value in the binary search tree, do nothing. You should keep the tree still a binary search tree after removal.…
题目: Given a root of Binary Search Tree with unique value for each node. Remove the node with given value. If there is no such a node with given value in the binary search tree, do nothing. You should keep the tree still a binary search tree after rem…
从BST中移除一个节点是比较复杂的问题,需要分好几种情况讨论. 如这篇文章,就讨论了删除节点 1.有无左右子树 2.只有右子树 3.只有左子树 三种情况. 一种简单些的思维是只考虑删除节点是否有右子树(因为第一个比删除节点大的节点可能出现在右子树,不会出现在左子树). 这里用Target表示删除节点,Parent表示删除节点的母节点. 1. 没有右子树 Parent.left / Parent.right = Target.left 2. 有右子树 1) 找到第一个比删除节点大的节点Node 2…
The solution for the problem can be divided into three cases: case 1: if the delete node is leaf node, then we can simply remove it case 2: if the delete node is has single side or substree case 3: it has two children, then to keep it as a valid bina…
题目: Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with…
题意 略 分析 1.首先要了解到BST的中序遍历是递增序列 2.我们用一个临时节点tmp储存p的中序遍历的下一个节点,如果p->right不存在,那么tmp就是从root到p的路径中大于p->val的最小数,否则就遍历p的右子树,找到最左边的节点即可 代码 class Solution { public: /* * @param root: The root of the BST. * @param p: You need find the successor node of p. * @re…
/// Binary Search Tree - Implemenation in C++ /// Simple program to create a BST of integers and search an element in it #include<iostream> #include "cstdio" #include "queue" using namespace std; ///Definition of Node for Binary…
Given a binary search tree and a new tree node, insert the node into the tree. You should keep the tree still be a valid binary search tree. Example Given binary search tree as follow: 2 / \ 1 4 / 3 after Insert node 6, the tree should be: 2 / \ 1 4…
Binary Tree: 0到2个子节点; Binary Search Tree: 所有左边的子节点 < node自身 < 所有右边的子节点: 1. Full类型: 除最下面一层外, 每一层都有两个子节点: 2. Complete类型: 除最下面一层外为Full类型, 但是最下面一层最所有子节点靠左: 3. Balanced类型: 左右两个子树的长度相差小于等于一: /** * Definition of TreeNode: * public class TreeNode { * public…
Validate Binary Search Tree Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node c…