LeetCode(40)-Merge Sorted Array】的更多相关文章

听到初爱有感 开头啰嗦两句,刚在做算法题目的时候,听到了杨宗纬的<初爱>,突然有了一种本科时候的感觉,想想自己现在研二了,青春喂了狗,我果断喝了一罐啤酒,循环这首歌到吐-.. 题目: Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: You may assume that nums1 has enough space (size that is g…
题目 Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements i…
题目 Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 分析 给定一个有序序列,构造一颗平衡的二叉查找树. 思想:序列中值构造根节点,递归,前半序列构造左子树,有伴序列构造右子树. AC代码 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNod…
1.题目 88. Merge Sorted Array——Easy Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array. Note: The number of elements initialized in nums1 and nums2 are m and n respectively. You may assume that nums1 has enough…
题目 Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 分析 合并k个有序链表. 我们从数据结构的链表章节学会了如何合并两个链表,针对此题,一个简单的解法便是遍历k次,两个链表合并,合并后的结果与下一个链表合并: 此时时间复杂度为O(nk),遗憾,提交会出现TLE. 所以,必须另觅他法,我们知道排序领域中很多方法都可以提高性能比如合并排序性能为O(n…
题目 Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 分析 数据结构与算法的链表章节的典型实例,将两个有序链表合成一个,保持其有序的性质. AC代码 /** * Definition for singly-linked list. * struct ListNod…
Medium! 题目描述: 给定一个数组 candidates 和一个目标数 target ,找出 candidates 中所有可以使数字和为 target 的组合. candidates 中的每个数字在每个组合中只能使用一次. 说明: 所有数字(包括目标数)都是正整数. 解集不能包含重复的组合. 示例 1: 输入: candidates = [10,1,2,7,6,1,5], target = 8, 所求解集为: [ [1, 7], [1, 2, 5], [2, 6], [1, 1, 6] ]…
#-*- coding: UTF-8 -*-class Solution(object):    def merge(self, nums1, m, nums2, n):        """        :type nums1: List[int]        :type m: int        :type nums2: List[int]        :type n: int        :rtype: void Do not return anything,…
void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) { ; ; ; && j >= ) { if (nums1[i] > nums2[j]) nums1[k--] = nums1[i--]; else nums1[k--] = nums2[j--]; } ) nums1[k--] = nums2[j--]; }…
题目 Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Solve it without division and in O(n). For example, given [1,2,3,4], return [24,12,8,6].…