啦啦啦,水一发准备去复习功课~ ------------------------------------------水一发的分割线------------------------------------------ http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1514 水题,没有一次AC我很惭愧,竟然忘了输出总共的个数..... #include<cstdio> #include<cstring> const…

两题水题: 1.如果一个数能被分解为两个素数的乘积,则称为Semi-Prime,给你一个数,让你判断是不是Semi-Prime数. 2.定义F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2) 让你判断第n项是否能被3整除. 1.ZOJ 2723 Semi-Prime http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1723 打表即可. #include<cstdio>…

水 Information Entropy Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge Information Theory is one of the most popular courses in Marjar University. In this course, there is an important chapter about information entropy. Entropy is…

水 Average Score Time Limit: 2 Seconds      Memory Limit: 65536 KB Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bob was anxious about hi…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=3702 题目大意: 对于给定的一个字符串,满足如下要求输出AC,否则WA(好吧我简写) 给定字符串只有ZOJ三个字母组成.Z和J只能有一个并且Z在左边 J之后的O个数必须大于Z之前的O个数 Z和J之间O的个数必须不大于J之后的O的个数,并且他们都大于0 #include<cstdio> #include<cstring> const int MAXN=1001;…

再水一发,舍友肿么还在睡T T. ---------------------------------舍友还在睡觉的分割线--------------------------------- http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=3200 大意:给你一串字符串,要求你按'Z''O''J''7'+'其他字符'排好序. 代码不太美观.不过还好啦. 不要像题目说的那样傻傻的排序,直接数个数就可以啦.输出的时候不是那四个字母就输…

Information Entropy Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3827 Description Information Theory is one of the most popular courses in Marjar University. In this course, there is an impo…

GCD Reduce Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge You are given a sequence {A1, A2, ..., AN}. You task is to change all the element of the sequence to 1 with the following operations (you may need to apply it multiple ti…

LINK:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3787 思路:结构体 时间转化为秒记录下最小并且排序就好了 /** @Date : 2017-03-23-22.06 * @Author : Lweleth (SoungEarlf@gmail.com) * @Link : https://github.com/ * @Version : */ #include<bits/stdc++.h> #define LL…

题目链接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3932 题意 给出 N 个人,然后 1-N 然后 从 1 - N 一个一个的进,每个人 进去 都可以在在座的人握手,然后给出那个人握手的次数 要求出 握手次数的最大值 思路 只要进来的人握手次数>=1 那么 本来已经在区域内的人 那个当前这个人的握手次数 就是其给出的握手次数,本来已经在区域内的人握手次数都+1,因为都是有可能的 然后实际发现 ,可以FOR 一遍…

题意:给定 n 个密码,你要按长度不递减的顺序进行尝试,问你最多和最少试多少次可能找出密码,每尝试 k 次错误的,就要等5秒. 析:我们只要把长度全都统计下来,然后从1开始去找目标长度,最少的就是正好到目标长度,最多的就是把目标长度恰好试完. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <…

Average Score Time Limit: 2 Seconds      Memory Limit: 65536 KB Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especially in Mathematical Analysis. After a mid-term exam, Bob was anxious about his…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1727 题目大意: 给你书名.出版时间.价格,让你按照一定的顺序排序.. 其中题目会给出优先级最高的,剩下两个按书名优先级>出版时间>价格来排序. 思路: 练习sort重载的... 不过sort(book,book+n,cmp_by_name);的重载函数竟然不能用引用..不然会cp好吧,我习惯写重载<运算符了. #include<cstdio> #incl…

2679:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1679 2952:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1951 ZOJ:2679先来~ 水题大意:(题目大意:我什么时候改名了哇T T) 给你一个5位数的中间三个字母,还有一个数N让你求能被N整除的最大的五位数. 思路: 直接暴力枚举.... #include<cstdio> int…

首先还是书写本文的 参考档:http://www.cnblogs.com/mchina/archive/2013/01/01/2840815.html 工具介绍:原文为官方英文解释本人给翻译下 数量最大的安全漏洞之一是密码,每个密码安全研究显示. Hydra是一个parallized登录的裂解装置,它支持众多的协议来攻击.新的模块很容易的添加,旁边,它是灵活的,而且速度非常快. 水润测试上编译的Linux,Windows/ Cygwin的中,Solaris 11中的FreeBSD8.1和OSX,…

Valid Palindrome吐槽一下Leetcode上各种不定义标准的输入输出(只是面试时起码能够问一下输入输出格式...),此篇文章不是详细的题解,是自己刷LeetCode的一个笔记吧,尽管没有代码,可是略微难一点的都会标出主要思路,便于以后复习 PS:题目中有"水题"两字的都是一遍AC,没有标注的都说明了问题,顺序依照Leetcode上时间倒序排列,少量题目因为和之前的题目有相关性,因此将其放在一起,比方12题和13题,因此中间可能会"缺少"几道题目,缺少的…

一.前言 前面阐述了服务器的总体框架,下面来分析服务器的所有父类ZooKeeperServer. 二.ZooKeeperServer源码分析 2.1 类的继承关系 public class ZooKeeperServer implements SessionExpirer, ServerStats.Provider {} 说明:ZooKeeperServer是ZooKeeper中所有服务器的父类,其实现了Session.Expirer和ServerStats.Provider接口,Session…

一.前言 前面阐述了服务器的总体框架,下面来分析服务器的所有父类ZooKeeperServer. 二.ZooKeeperServer源码分析 2.1 类的继承关系 public class ZooKeeperServer implements SessionExpirer, ServerStats.Provider {} 说明:ZooKeeperServer是ZooKeeper中所有服务器的父类,其实现了Session.Expirer和ServerStats.Provider接口,Session…

The Best Hacking Tools Hacking Tools : List of security tools specifically aimed toward security professionals for testing and demonstrating security weaknesses.     Passwords Cain & Abel Cain & Abel is a password recovery tool for Microsoft Opera…

题目传送门 /* 水题:找排序找中间的价格,若有两个,选价格大的: 写的是有点搓:) */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <string> #include <map> #include <set> #include <queue…

题目传送门 /* 水题:已知1928年1月1日是星期日,若是闰年加1,总天数对7取余判断就好了: */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <string> #include <map> #include <set> #include <…

题目传送门 /* 水题:) */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include <string> #include <map> #include <set> #include <queue> #include <vector>…

题目传送门 水题,找出出现次数最多的数字,若多个输出Nobody //#include <bits/stdc++.h> //using namespace std; #include <cstdio> //stdio.h #include <cstring> //string.h #include <algorithm> const int N = 1e3 + 5; struct Hash { int num, cnt; bool operator <…

Description A boolean matrix has the parity property when each row and each column has an even sum, i.e. contains an even number of bits which are set. Here's a 4 x 4 matrix which has the parity property: 1 0 1 0 0 0 0 0 1 1 1 1 0 1 0 1 The sums of t…

In computer science, the Knuth-Morris-Pratt string searching algorithm (or KMP algorithm) searches for occurrences of a "word" W within a main "text string" S by employing the observation that when a mismatch occurs, the word itself em…

ZOJ 2819 Average Score Time Limit: 2 Sec  Memory Limit: 60 MB 题目连接 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5373 Description Bob is a freshman in Marjar University. He is clever and diligent. However, he is not good at math, especia…

LINK:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3778 题意:有n道菜,每道菜需要\(a_i\)道工序,有m个锅可以同时做不同菜,问最小时间. 思路:水题,但要注意最小需要的时间显然是最大的\(a_i\)值,剩下的就是求个均,求个余的事了. /** @Date : 2017-03-24-14.35 * @Author : Lweleth (SoungEarlf@gmail.com) * @Link : http…

The balance was the first mass measuring instrument invented. In its traditional form, it consists of a pivoted horizontal lever of equal length arms, called the beam, with a weighing pan, also called scale, suspended from each arm (which is the orig…

There are N little kids sitting in a circle, each of them are carrying some java beans in their hand. Their teacher want to select M kids who seated in M consecutive seats and collect java beans from them. The teacher knows the number of java beans e…

MightyHorse is playing a music game called osu!. After playing for several months, MightyHorse discovered the way of calculating score in osu!: 1. While playing osu!, player need to click some circles following the rhythm. Each time a player clicks,…