Tricks Device 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5294 Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the entrance of the tomb while Dumb Zhang's at the end of it. The tomb is made up of many chambers, th…

分析题意可知: 1.最少须要切断多少边使吴不能找到张(题意吴仅仅能走最短路径上面的边),对从起点到终点的最短路径又一次建图,每条边的权值为1.求最大流就可以 2.在吴能够找到张的前提下,最多能够切断边的数量:仅仅须要在全部最短路径中寻找一条经过边数量最少的最短路径,用边的总数减去它就可以(逆向思维) 代码例如以下: #include <cstdio> #include <cstring> #include <vector> #include <queue>…

Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 124    Accepted Submission(s): 27 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the entr…

链接:http://acm.hdu.edu.cn/showproblem.php?pid=5294 Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 375    Accepted Submission(s): 98 Problem Description Innocent Wu follows Dumb Zh…

题目链接:HDU 5294 Tricks Device 题意:n个点,m条边.而且一个人从1走到n仅仅会走1到n的最短路径.问至少破坏几条边使原图的最短路不存在.最多破坏几条边使原图的最短路劲仍存在 思路: 1.跑一遍最短路.记录下全部最短路径,将这些最短路径的边以(0,1)(流量,容量)加到网络流中,跑一遍最大流 2.记录下的全部最短路径,再加到新的最短路的图中,边权为1,跑一遍最短路.m-最短路 就是答案 注意:有重边的情况 比方: 2 3 1 2 1 1 2 1 1 2 1 ans: 3…

Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 389    Accepted Submission(s): 100 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the ent…

题目传送门 /* 题意:一无向图,问至少要割掉几条边破坏最短路,问最多能割掉几条边还能保持最短路 SPFA+Dinic:SPFA求最短路时,用cnt[i]记录到i最少要几条边,第二个答案是m - cnt[n] 最大流==最小割,套个Dinic模板,以后再理解算法... */ #include <cstdio> #include <algorithm> #include <cstring> #include <queue> #include <vecto…

最短路记录路径,同一时候求出最短的路径上最少要有多少条边, 然后用在最短路上的边又一次构图后求最小割. Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1584    Accepted Submission(s): 388 Problem Description Innocent Wu follows Dum…

Tricks Device Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 0    Accepted Submission(s): 0 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu’s at the entrance…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5294 Problem Description Innocent Wu follows Dumb Zhang into a ancient tomb. Innocent Wu's at the entrance of the tomb while Dumb Zhang's at the end of it. The tomb is made up of many chambers, the total…