Leetcode: Non-overlapping Intervals】的更多相关文章

Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 题目标签:Array 这道题目给了我们一个区间的list,让我们返回一个list,是合并了所有有重叠的区间之后的list.这道题目的关键在于如何判断两个区间有重叠,根据原题给的例子可以看出,在按照每个区间的start排序…
Merge Intervals题解 原创文章,拒绝转载 题目来源:https://leetcode.com/problems/merge-intervals/description/ Description Given a collection of intervals, merge all overlapping intervals. Example Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. Solution…
Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18].     先排序,然后循环合并   /** * Definition for an interval. * struct Interval { * int start; * int end;…
Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 思路:开始想用线段树,后来想想这个不是动态变化的没必要. 按区间的第一个值从小到大排序,然后跳过后面被覆盖的区间来找. sort折腾了好久,开始搞不定只好自己写了一个归并排序.现在代码里的sort是可用的. class…
Given a collection of intervals, merge all overlapping intervals. For example, Given [1,3],[2,6],[8,10],[15,18], return [1,6],[8,10],[15,18]. 解题思路一: 用两个指针startIndex和endIndex来维护每次添加intervals的start和end的位置,然后分类讨论即可,JAVA实现如下: public List<Interval> merge…
Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 问题:给定一个区间集合,整合所有重叠的区间. 对区间集合按照 start 来排序,然后根据 intervals[i].start 和 res.lastElement.end 来整合即可. int static comp(…
题目:给定一连串的区间,要求输出不重叠的区间. Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 这题主要会要知道如何对一个node型或者是struct进行排序.就是如何定义sort的比较函数,sort的比较函数本来默认的是小于函数,现在给定的struct类型没有定义的…
Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 思路: 我们首先要做的就是给区间集排序,由于我们要排序的是个结构体,所以我们要定义自己的comparator,才能用sort来排序,我们以start的值从小到大来排序,排完序我们就可以开始合并了,首先把第一个区间存入结果…
Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6]. 题意: 给定一些区间,将重叠部分合并. 思路: 将原in…
Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 解题思路: 根据start对区间进行排序,然后依次遍历进行区间合并. /** * Definition for an interval. * struct Interval { * int…