package Basic; import java.util.Scanner; public class Gcd { public static void main(String[] args) { Scanner scanner=new Scanner(System.in); int num_1=scanner.nextInt(); int num_2=scanner.nextInt(); if(num_1>num_2){ System.out.println(gcd(num_1, num_…
#欧几里得求最大公约数 #!/usr/bin/env python #coding -*- utf:8 -*- #iteration def gcd(a,b): if b==0: return a else: return gcd(b, remainder(a, b)) #此方法仅仅书用于a和b都为正数 def gcd_1(a,b): while(b>0): rem = remainder(a,b) a = b b = rem return a def remainder(x,y): retur…
求最大公约数哪个强,果断GCD,非递归版本和递归版本如下: #include<iostream> using namespace std; int gcd(int a, int b){ //非递归版本 int big = max(a, b); int small = min(a, b); int temp; while(small != 0 ){ temp = big % small; big = small; small = temp; } return big; } int gcd_(in…
GCD nyoj 1007 (欧拉函数+欧几里得) GCD 时间限制:1000 ms | 内存限制:65535 KB 难度:3 描述 The greatest common divisor GCD(a,b) of two positive integers a and b,sometimes written (a,b),is the largest divisor common to a and b,For example,(1,2)=1,(12,18)=6.(a,b) can be…
1.欧几里得算法(辗转相除法) 直接上gcd和lcm代码. int gcd(int x,int y){ ?x:gcd(y,x%y); } int lcm(int x,int y){ return x*y/gcd(x,y); } 2.扩欧:exgcd:对于a,b,一定存在整数对(x,y)使ax+by=gcd(a,b)=d ,且a,b互质时,d=1. x,y可递归地求得. 我懒得改返回值类型了 long long exgcd(long long a,long long b,long long &x,…
ZOJ Problem Set - 3593 http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3593 One Person Game Time Limit: 2 Seconds Memory Limit: 65536 KB There is an interesting and simple one person game. Suppose there is a number axis under your f…
