Xcode更新到7.3后会出现NSObject+MJProperty.h报Cannot create __weak reference in file using manual reference counting错误信息. 解决的办法:在Build Settings--------->Aplle LLVM7.1 - Language - Objectibe-C------------->Weak Reference In Manual Retain Release设置为YES.…

  原帖地址 http://stackoverflow.com/questions/36147625/xcode-7-3-cannot-create-weak-reference-in-file-using-manual-reference-counting activeoldestvotes up vote87down voteaccepted Set Build Settings -> Apple LLVM 7.1 - Language - Objective C -> Weak Refe…

解决的办法:在Build Settings--------->Aplle LLVM8.0 - Language - Objectibe-C------------->Weak Reference In Manual Retain Release 设置为YES.…

之前的编程没有遇到过,应该是苹果官方那边又做了新规吧. 不过不要紧,只要根据这个就能解决报错问题.  Set Build Settings -> Apple LLVM 7.1 - Language - Objective C -> Weak References in Manual Retain Release to YES.    参考: http://blog.csdn.net/sjcode/article/details/51014679…

http://blog.csdn.net/ouq68/article/details/51003876 解决方法: Please set ‘Weak References in Manual Retain Release:YES’.…

https://docs.mongodb.org/manual/reference/operator/aggregation/unwind/#examples http://www.clusterdb.com/mongodb/joins-and-other-aggregation-enhancements-in-mongodb-3-2…

FATAL: UNABLE TO CREATE ‘…GIT/INDEX.LOCK’ FILE EXISTS Hi, Today I will share you my other experience using git control system, it happened to me after I’ve created a branch, when adding my changes to remote or even committed my file I’ve started to s…

参考博文:链接 ArcCatalog连接ArcSDE连接报:unable to create new database connection file,permission is denied 最近经常碰到这个问题,当使用ArcGIS10.2(可能跟版本无关)连接SDE时,会碰到一个错误: unable to create new database connection file,permission is denied. 这个问题很诡异,因为创建企业级地理数据库成功,但是连接SDE出现问题,细…

Git – fatal: Unable to create ‘/.git/index.lock’: File exists. fatal: Unable to create ‘/path/my_proj/.git/index.lock’: File exists. If no other git process is currently running, this probably means a git process crashed in this repository earlier. M…

Question:How to reference two table when lack reference column. Example: 1.Create two tables the one of  lack reference column. CREATE TABLE t1( t_id NUMBER, t_age NUMBER );INSERT INTO t1 VALUES(1,24);COMMIT; CREATE TABLE t2( t_name VARCHAR2(20) ); I…