1023 Have Fun with Numbers (20 分)   Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactl…

1023 Have Fun with Numbers (20)(20 分) Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exac…

1023 Have Fun with Numbers(20 分) Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly t…

PAT (Advanced Level) Practice 1023 Have Fun with Numbers (20 分) 凌宸1642 题目描述: Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be…

1023 Have Fun with Numbers(20 分) Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly t…

1023 Have Fun with Numbers (20 分)   Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactl…

1023. Have Fun with Numbers (20) 时间限制 400 ms 内存限制 32000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913…

1023 Have Fun with Numbers (20 分)   Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactl…

https://pintia.cn/problem-sets/994805342720868352/problems/994805478658260992 Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to b…

题目 Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly the numbers from 1 to 9, only i…

手动模拟一下高精度加法. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<vector> using namespace std; ],t[],c[]; int lens,lenc; void f(cha…

和1024一样都是大数据的题,因为位数最多要20位,long long最多19位给一个num,求sum=num+num问sum包含的数字,是否是num的一个排列,即数字都一样,只是顺序不同罢了. #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <string> using namespace std; ; struct…

题意: 输入一个不超过20位的正整数,问乘2以后是否和之前的数组排列相同(数字种类和出现的个数不变),输出Yes或No,并输出乘2后的数字. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; string s; ]; int main(){ cin>>s; int len=s.size(); ;i>=;--i) ++vis[s[i]-'…

1023 组个最小数 (20)(20 分) 给定数字0-9各若干个.你可以以任意顺序排列这些数字,但必须全部使用.目标是使得最后得到的数尽可能小(注意0不能做首位).例如:给定两个0,两个1,三个5,一个8,我们得到的最小的数就是10015558. 现给定数字,请编写程序输出能够组成的最小的数. 输入格式: 每个输入包含1个测试用例.每个测试用例在一行中给出10个非负整数,顺序表示我们拥有数字0.数字1.--数字9的个数.整数间用一个空格分隔.10个数字的总个数不超过50,且至少拥有1个非0的数…

problem Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly the numbers from 1 to 9, o…

Have Fun with Numbers Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly the numbers…

给定数字0-9各若干个.你可以以任意顺序排列这些数字,但必须全部使用.目标是使得最后得到的数尽可能小(注意0不能做首位).例如:给定两个0,两个1,三个5,一个8,我们得到的最小的数就是10015558. 现给定数字,请编写程序输出能够组成的最小的数. 输入格式: 每个输入包含1个测试用例.每个测试用例在一行中给出10个非负整数,顺序表示我们拥有数字0.数字1.……数字9的个数.整数间用一个空格分隔.10个数字的总个数不超过50,且至少拥有1个非0的数字. 输出格式: 在一行中输出能够组成的最小…

给定数字0-9各若干个.你可以以任意顺序排列这些数字,但必须全部使用.目标是使得最后得到的数尽可能小(注意0不能做首位).例如:给定两个0,两个1,三个5,一个8,我们得到的最小的数就是10015558. 现给定数字,请编写程序输出能够组成的最小的数. 输入格式: 每个输入包含1个测试用例.每个测试用例在一行中给出10个非负整数,顺序表示我们拥有数字0.数字1.--数字9的个数.整数间用一个空格分隔.10个数字的总个数不超过50,且至少拥有1个非0的数字. 输出格式: 在一行中输出能够组成的最小…

简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; ][]={ "tret","jan", "f…

生词以及在文中意思 duplication 重复 permutation 排列 property 属性 import java.util.Scanner; public class Main { public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc=new Scanner(System.in); String s=sc.next(); int [] a=new int[s.le…

https://pintia.cn/problem-sets/994805260223102976/problems/994805298269634560 给定数字0-9各若干个.你可以以任意顺序排列这些数字,但必须全部使用.目标是使得最后得到的数尽可能小(注意0不能做首位).例如:给定两个0,两个1,三个5,一个8,我们得到的最小的数就是10015558. 现给定数字,请编写程序输出能够组成的最小的数. 输入格式: 每个输入包含1个测试用例.每个测试用例在一行中给出10个非负整数,顺序表示我们…

没什么好说的,注意字符串的处理,以及当数字是13的倍数时,只需高位叫法的单词.比如26,是“hel”,而不是“hel tret”. 代码: #include <iostream> #include <cstdio> #include <algorithm> #include <map> #include <string> #include <string.h> using namespace std; ][]={"tret&…

题意: 给定一个正整数(最多有20位),假设这个数是a1a2a3...ak,把这个数乘以2倍,看得到的结果是否仍然是a1a2a3...ak的一个排列    思路: 大整数与int型整数的乘法:简单哈希. 代码: #include <cstdio> #include <cstring> struct bign{ ]; int len; bign(){ memset(digit,,sizeof(digit)); len=; } }; bign change(char str[]) {…

[题目大意] 给一个不超过20位的数字,如果将它乘以2得到的数仅仅是原来的数字重新排列得到的,那就输出Yes,下一行输出加倍后的数.如果不是,输出No,下一行输出加倍后的数. [思路] 20位过于庞大,超出了long long,所以用数组来做,其中的算法核心有竖式乘法的数组计算法. [tips] 1 判断原数和double原数是否拥有同样数字的方法: 建立一个数组check[0~9],如果原数的第i位是a,则check[a]++:如果double原数的第i位是a,则check[a]--.最后检查…

题意: 输入一个正整数N(<100),接着输入N组数据每组包括一行字符串,将其翻译为另一个星球的数字. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ][]={","tam","hel","maa","huh","tou","kes…

准备每天刷两题PAT真题.(一句话题解) 1001 A+B Format  模拟输出,注意格式 #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; string ans = ""; int main() { ; cin >> a >> b; c = a + b; ) {…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6102219.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 时隔两年,又开始刷题啦,这篇用于PAT甲级题解,会随着不断刷题持续更新中,至于更新速度呢,嘿嘿,无法估计,不知道什么时候刷完这100多道题. 带*的是我认为比较不错的题目,其它的难点也顶多是细节处理的问题~ 做着做着,发现有些题目真的是太水了,都不想写题解了…

树(23) 备注 1004 Counting Leaves   1020 Tree Traversals   1043 Is It a Binary Search Tree 判断BST,BST的性质 1053 Path of Equal Weight   1064 Complete Binary Search Tree 完全二叉树的顺序存储,BST的性质 1066 Root of AVL Tree 构建AVL树,模板题,需理解记忆 1079 Total Sales of Supply Chain…

1019. General Palindromic Number 题意:求数N在b进制下其序列是否为回文串,并输出其在b进制下的表示. 思路:模拟N在2进制下的表示求法,“除b倒取余”,之后判断是否回文. #include<iostream> #include<cstdio> using namespace std; ]; int main() { int n, b; scanf("%d%d", &n, &b); , tmp = n,yu=tmp…

早期部分代码用 Java 实现.由于 PAT 虽然支持各种语言,但只有 C/C++标程来限定时间,许多题目用 Java 读入数据就已经超时,后来转投 C/C++.浏览全部代码:请戳 本文谨代表个人思路,欢迎讨论;) 1021. Deepest Root (25) 题意 无环连通图也可以视为一棵树,选定图中任意一点作为根,如果这时候整个树的深度最大,则称其为 deepest root. 给定一个图,按升序输出所有 deepest root.如果给定的图有多个连通分量,则输出连通分量的数量. 分析…