Gerald is into Art Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to attach it to the wall and place the paintings on the board. The board has shape of an a…

B. Gerald is into Art Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset/problem/560/B Description Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought…

 Gerald is into Art time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bo…

B. Gerald is into Art Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/560/problem/B Description Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a…

B. Gerald is into Art time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he…

[CF简单介绍] 提交链接:http://codeforces.com/contest/560/problem/B 题面: B. Gerald is into Art time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Gerald bought two very rare paintings at the Sotheby's a…

B. Gerald is into Art time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he…

time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he bought a special board to…

http://codeforces.com/problemset/problem/567/A A. Lineland Mail time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output All cities of Lineland are located on the Ox coordinate axis. Thus, each cit…

A题,超级大水题,根据有没有1输出-1和1就行了.我沙茶,把%d写成了%n. B题,也水,两个矩形的长和宽分别加一下,剩下的两个取大的那个,看看是否框得下. C题,其实也很简单,题目保证了小三角形是正三角形,一个正三角的面积=l*l*(1/2)*cos(30),由于只要算三角形个数,把六边形扩成一个大三角,剪掉三个小三角,除一下系数就没了.就变成了平方相减. D题,根据定义递归.然后注意奇数就行了.我沙茶,没加第一种判断dfs(a+len,len,b+len) && dfs(a,len,b…

A. Currency System in Geraldion time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A magic island Geraldion, where Gerald lives, has its own currency system. It uses banknotes of several valu…

题目链接   A. Currency System in Geraldion 有1时,所有大于等于1的数都可由1组成.没有1时,最小不幸的数就是1. #include<iostream> #include<cstdio> #include<algorithm> using namespace std; void solve(){ int n,x; scanf("%d",&n); ; ; i<=n; i++){ scanf("%…

A题: 题目地址:Currency System in Geraldion 题意:给出n中货币的面值(每种货币有无数张),要求不能表示出的货币的最小值.若全部面值的都能表示,输出-1. 思路:水题,就是看看有没有面值为1的货币,假设有的话,全部面值的货币都能够通过1的累加得到,假设没有的话.最小的不能表示的就当然是1辣. #include <stdio.h> #include <math.h> #include <string.h> #include <stdli…

B. Gerald is into Art time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Gerald bought two very rare paintings at the Sotheby's auction and he now wants to hang them on the wall. For that he…

A. Currency System in Geraldion: 题意:有n中不同面额的纸币,问用这些纸币所不能加和到的值的最小值. 思路:显然假设这些纸币的最小钱为1的话,它就能够组成随意面额. 假设这些纸币的最小值大于1,那么它所不能组成的最小面额就是1.所以自学求最小值就可以. 我的代码: #include <set> #include <map> #include <cmath> #include <stack> #include <queue…

Atitit  图像处理Depixelizing Pixel Art像素风格画的矢量化 在去年的时候,偶然看到hqx算法. 一个高质量的插值放大算法. 与双线性插值等插值算法相比,这个算法放大后对人眼保护相对比较好. 没有双线性插值看起来模糊,固然,也抽空把算法简单优化了一下. 常规的图像填充采样放大 "经典"的图像填充采样放大,应用线性滤波器,或导出于分析插值理论.或导出于信号处理理论.使用滤波器的实例,比如"最近邻,Bicubic和Lancosz [ Wolberg 19…

Gerald's Hexagon Gerald got a very curious hexagon for his birthday. The boy found out that all the angles of the hexagon are equal to . Then he measured the length of its sides, and found that each of them is equal to an integer number of centimeter…

http://blogs.mathworks.com/loren/2007/03/01/creating-sparse-finite-element-matrices-in-matlab/ Loren on the Art of MATLAB March 1st, 2007 Creating Sparse Finite-Element Matrices in MATLAB I'm pleased to introduce Tim Davis as this week's guest blogge…

这几天在做一个项目时需要在Android中使用OSGi框架(Apache Felix),于是在一个android 4.4.2 版本系统的某品牌的平板上实验. 实验内容很简单:把felix包里的felix.jar包和一些bundles的jar包用android sdk里的dx及aapt工具转化为包含dex字节码的jar 包.这样使这些jar包能在Android上跑起来.(因为Android上使用的是在Dalvik虚拟机而不是标准的java虚拟机,所以"原生"的 jar包不能直接在Andr…

原文地址: https://github.com/ZhaoKaiQiang/AndroidDifficultAnalysis/blob/master/10.ART%E3%80%81JIT%E3%80%81AOT%E3%80%81Dalvik%E4%B9%8B%E9%97%B4%E6%9C%89%E4%BB%80%E4%B9%88%E5%85%B3%E7%B3%BB%EF%BC%9F.md ART.JIT.AOT.Dalvik之间有什么关系? JIT与Dalvik JIT是"Just In Tim…

与 iOS 相比,Android 的用户体验有个相对糟糕的开始.在很长的时间里,界面一直丑小鸭,卡顿也是挥不去的痛.不过,在 Google 的全力推动,以及硬件厂商的响应下,Android 还是跨越各种阻碍,逐渐壮大起来了. 在此过程中,Google 也在经历着重大的变化.它逐渐从一个只重视数据的公司,转变为一个重视设计和用户体验的公司.从 Android 4.0 开始,Android 拥有了自己的设计语言和应用设计指导.与此同时,Google 也在着手解决卡顿问题.Android 4.1 的“…

Gerald and Giant Chess Problem's Link: http://codeforces.com/contest/559/problem/C Mean: 一个n*m的网格,让你从左上角走到右下角,有一些点不能经过,问你有多少种方法. analyse: BZOJ上的原题. 首先把坏点和终点以x坐标为第一键值,y坐标为第二键值排序 . 令fi表示从原点不经过任何坏点走到第i个点的个数,那么有DP方程: fi=Cxixi+yi−∑(xj<=xi,yj<=yi)C(xi−xj)…

Gerald's Hexagon Problem's Link: http://codeforces.com/contest/559/problem/A Mean: 按顺时针顺序给出一个六边形的各边长(且保证每个内角都是120度),求能够分解成多少个边长为1的小正三角形. analyse: 由于每个内角都是120度,那么把三条边延长相交,一定能够得到一个正三角形. 求出正三角形的面积S1和补上的小三角形的面积S2,则answer=S1-S2. 这里不是真正意义上求正三角形的面积,而是直接求内部可…

C. Gerald and Giant Chess time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Giant chess is quite common in Geraldion. We will not delve into the rules of the game, we'll just say that the ga…

C. Gerald's Hexagon Time Limit: 2 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/559/problem/A Description Gerald got a very curious hexagon for his birthday. The boy found out that all the angles of the hexagon are equal to . Then he me…

http://developer.51cto.com/art/200512/15883.htm…

鏈接:http://poj.org/problem?id=1279 Art Gallery Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 5337   Accepted: 2277 Description The art galleries of the new and very futuristic building of the Center for Balkan Cooperation have the form…

A Corrupt Mayor's Performance Art Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 100000/100000 K (Java/Others) Problem Description Corrupt governors always find ways to get dirty money. Paint something, then sell the worthless painting at a…

A Corrupt Mayor's Performance Art Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 100000/100000 K (Java/Others)Total Submission(s): 33    Accepted Submission(s): 11 Problem Description Corrupt governors always find ways to get dirty money. Pa…

C. Gerald's Hexagon time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Gerald got a very curious hexagon for his birthday. The boy found out that all the angles of the hexagon are equal to .…