描述 Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight). 输入是一个无符号整数,返回其二进制表达式中数字位数为 ‘1’ 的个数. 解析 消除最后的1 观察一下 n 与 n-1 这两个数的二进制表示:对于 n-1 这个数的二进制来说,相对于 n 的二进制,它的最末位的一个 1 会变成 0,最末位一个 1…

编写一个函数,输入是一个无符号整数,返回的是它所有 位1 的个数(也被称为汉明重量).例如,32位整数 '11' 的二进制表示为 00000000000000000000000000001011,所以函数返回3. 详见:https://leetcode.com/problems/number-of-1-bits/description/ Java实现: public class Solution { // you need to treat n as an unsigned value publ…

Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…

Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…

Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…

题目描述 编写一个函数,输入是一个无符号整数,返回其二进制表达式中数字位数为 '1' 的个数(也被称为汉明重量). 示例 : 输入: 11 输出: 3 解释: 整数 11 的二进制表示为 00000000000000000000000000001011 示例 2: 输入: 128 输出: 1 解释: 整数 128 的二进制表示为 00000000000000000000000010000000 思路 思路一: 用Integer.bitCount函数统计参数n转成2进制后有多少个1 public…

lc 191 Number of 1 Bits 191 Number of 1 Bits Write a function that takes an unsigned integer and returns the number of '1' bits it has (also known as the Hamming weight). For example, the 32-bit integer '11' has binary representation 0000000000000000…

Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…

Problem: Write a function that takes an unsigned integer and returns the number of '1' bits it has (also known as the Hamming weight). For example, the 32-bit integer '11' has binary representation 00000000000000000000000000001011, so the function sh…

题目: Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 右移32次 计算末尾的1的个数 转成二进制统计1的个数 使用mask 日期 [LeetCode] 题目地址:https://leetcode.com/problems/number-of-1-bits/ Total Accepted: 88721 Total Submissions: 236174 Difficulty: Easy 题目描述 Writ…

Number of 1 Bits Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight). Example 1: Input: 00000000000000000000000000001011 Output: 3 Explanation: The input binary string 0000000000…

Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…

Number of 1 Bits Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the fun…

题目描述: Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function shoul…

Write a function that takes an unsigned integer and returns the number of '1' bits it has (also known as the Hamming weight). For example, the 32-bit integer '11' has binary representation 00000000000000000000000000001011, so the function should retu…

题目: Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Write a function that takes an unsigned integer and returns the number of '1' bits it has (also known as the Hamming weight). For example, the 32-bit integer…

Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…

［抄题］: Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function shoul…

Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight). Example 1: Input: 00000000000000000000000000001011 Output: 3 Explanation: The input binary string 000000000000000000000000000…

题意:给你一个整数,计算该整数的二进制形式里有多少个“1”.比如6(110),就有2个“1”. 一开始我就把数字n不断右移,然后判定最右位是否为1,是就cnt++,否则就继续右移直到n为0. 可是题目说了是无符号整数,所以给了2147483648,就WA了. 因为java里的int默认当做有符号数来操作,而2147483648超过int的最大整数,所以在int里面其实是当做-1来计算的. 那么,不能在while里面判断n是否大于0,和使用位操作符>>.应该使用位操作符>>>,…

#-*- coding: UTF-8 -*- class Solution(object):    def hammingWeight(self, n):        if n<=0:return n        mid=[]        while True:            if n==0:break            n,mod=divmod(n,2)            mid.append(mod)        mid.reverse()        return…

题意: 提供一个无符号32位整型uint32_t变量n,返回其二进制形式的1的个数. 思路: 考察二进制的特性,设有k个1,则复杂度为O(k).考虑将当前的数n和n-1做按位与,就会将n的最后一个1去掉,重复这样的操作就可以统计出1的个数了.(2015年春季 小米实习生的笔试题之一) class Solution { public: int hammingWeight(uint32_t n) { ; while(n) { n&=n-; cnt++; } return cnt; } }; AC代码…

190 - Reverse Bits Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up…

版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C#版 - Leetcode 191. Number of 1 Bits题解 191. 位1的个数 在线提交: https://leetcode-cn.com/problems/number-of-1-bits/description/ 题目描述 编写一个函数,输入是一个无符号整数,返回其二进制表达式中数字位数为…

位运算相关 三道题 231. Power of Two Given an integer, write a function to determine if it is a power of two. (Easy) 分析: 数字相关题有的可以考虑用位运算,例如&可以作为筛选器. 比如n & (n - 1) 可以将n的最低位1删除,所以判断n是否为2的幂,即判断(n & (n - 1) == 0) 代码: class Solution { public: bool isPowerOf…

191. Number of 1 Bits Easy Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight). Example 1: Input: 00000000000000000000000000001011 Output: 3 Explanation: The input binary string…

Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. Example 1: Input: 5 Output: True Explanation: The binary representation of 5 is: 101 Example 2: Input: 7 Output: False Ex…

Write a function that takes an unsigned integer and return the number of '1' bits it has (also known as the Hamming weight). Example 1: Input: 00000000000000000000000000001011 Output: 3 Explanation: The input binary string 000000000000000000000000000…