动态规划里例题,硬币问题. p[i] = dp[i - coin[j]] + 1; 注意i < coin[j] dp[i-coin[j]]无解都要跳过. public class Solution { public int coinChange(int[] coins, int amount) { int[] dp = new int[amount+1]; Arrays.fill(dp,Integer.MAX_VALUE); //dp[i] = dp[i - coin[j]] + 1; dp[0…