We Love MOE Girls Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 572    Accepted Submission(s): 378 Problem Description Chikami Nanako is a girl living in many different parallel worlds. In this…
A Bit Fun Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1148    Accepted Submission(s): 644 Problem Description There are n numbers in a array, as a0, a1 ... , an-1, and another number m. We d…
We Love MOE Girls Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 208    Accepted Submission(s): 157 Problem Description Chikami Nanako is a girl living in many different parallel worlds. In this…
A Bit Fun Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 423    Accepted Submission(s): 270 Problem Description There are n numbers in a array, as a0, a1 ... , an-1, and another number m. We de…
F(x) Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 382    Accepted Submission(s): 137 Problem Description For a decimal number x with n digits (AnAn-1An-2 ... A2A1), we define its weight as F(x…
G(x) Time Limit: 2000/500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 184    Accepted Submission(s): 44 Problem Description For a binary number x with n digits (AnAn-1An-2 ... A2A1), we encode it as Where ""…
Minimum palindrome Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 260    Accepted Submission(s): 127 Problem Description Setting password is very important, especially when you have so many "in…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4737 题目大意:给定一系列数,F(i,j)表示对从ai到aj连续求或运算,(i<=j)求F(i,j)<=m的总数. 解题思路:或运算只会让值变大或保持不变.不断通过右移j来更新F(i,j),当aj>=m时所有的i<=j F(i,j)都大于等于m,因此从j后面继续扫数组:当aj<m而F(i,j)>=m时通过右移i来使F(i,j)<m.扫完整个数组即可. #include…
题目大意:用m个字母组成一个长度为N的字符串,使得最长的回文子串 的长度最小. 并且要求字典序最小. 思路:分类模拟. 当M为1 的时候就直接输出N个A 当M大于2的时候就循环ABC 当M等于2的时候 先枚举出当N<9 的情况,因为此时可以用最长串长度为 3 的基础上得到. 而当N>9的时候. 其实就是 aababb 为循环节的一个循环.但是此时是建立在最长串为4的基础上得到 但是有另外的情况就是 m==2 n%6<=4的时候最后面就不是循环循环节了. 例如: m=2 n=10 aaba…
Theme Section Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 271    Accepted Submission(s): 121 Problem Description It's time for music! A lot of popular musicians are invited to join us in the…