problem 541. Reverse String II 题意: 给定一个字符串,每隔k个字符翻转这k个字符,剩余的小于k个则全部翻转,否则还是只翻转剩余的前k个字符. solution1: class Solution { public: string reverseStr(string s, int k) { int n = s.size(); int cnt = n / k; ; i<=cnt; i++) { ==) { if(i*k+k<n) reverse(s.begin()+i…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 题目地址:https://leetcode.com/problems/reverse-string-ii/#/description 题目描述 Given a string and an integer k, you need to reverse the first k characters for every…

原题地址: 344 Reverse String: https://leetcode.com/problems/reverse-string/description/ 541 Reverse String II: https://leetcode.com/problems/reverse-string-ii/description/ 题目&&解法: 1.Reverse String: Write a function that takes a string as input and ret…

344. Reverse String 最基础的旋转字符串 class Solution { public: void reverseString(vector<char>& s) { if(s.empty()) return; ; ; while(start < end){ char tmp = s[end]; s[end] = s[start]; s[start] = tmp; start++; end--; } return; } }; 541. Reverse Strin…

package leadcode; /** * 541. Reverse String II * Easy * 199 * 575 * * * Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters lef…

[Question] Write a function that takes a string as input and returns the string reversed. Example: Given s = "hello", return "olleh". [My Solution] Slice 切片 class Solution(object): def reverseString(self, s): """ :type s…

problem 344. Reverse String solution: class Solution { public: void reverseString(vector<char>& s) { vector<'); ; i>=; i--) { temp[i] = s[s.size()-i-]; } ; i<s.size(); i++) { s[i] = temp[i]; } } }; solution2: class Solution { public: vo…

Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or eq…

problem 557. Reverse Words in a String III solution1:字符流处理类istringstream. class Solution { public: string reverseWords(string s) { string ans = "", t = ""; istringstream is(s);// while(is >> t) { reverse(t.begin(), t.end()); ans…

Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or eq…