题意:      题意就是最基础的2sat,关系只有矛盾关系,然后二选一,关键是这个题目是输出字典序最小的那组解. 思路:      输出字典序最小,用强连通那个实现不了(起码没看到有人实现),其实我们可以直接暴力,我们可以给某个点染色,分成无色(W)红色(R)和蓝色(B)红色是我们要的答案,对于每一个点我们先尽可能的吧他的a染成红色,把他的~a染成蓝色,如果发现矛盾,就是出现a是蓝色的了,那么我们就把当前这个连通块重新清成W吧其实点换成~a这样在继续染色,如果还是不行,那么就证明无解.否则这样…

这个题我看了,都是推荐的神马双向广搜,难道这个深搜你们都木有发现?还是特意留个机会给我装逼? Open the Lock Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3014    Accepted Submission(s): 1323 Problem Description Now an emergent task for you…

Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 149833    Accepted Submission(s): 39945 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…

Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 59468   Accepted: 24750 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…

Peaceful Commission Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1948    Accepted Submission(s): 560 Problem Description The Public Peace Commission should be legislated in Parliament of Th…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1814 Problem Description The Public Peace Commission should be legislated in Parliament of The Democratic Republic of Byteland according to The Very Important Law. Unfortunately one of the obstacles is t…

http://acm.hdu.edu.cn/showproblem.php?pid=5311 Hidden String Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 1499    Accepted Submission(s): 534 Problem Description Today is the 1st anniversar…

题目链接:传送门 题目: Counting Cliques Time Limit: / MS (Java/Others) Memory Limit: / K (Java/Others) Total Submission(s): Accepted Submission(s): Problem Description A clique is a complete graph, in which there is an edge between every pair of the vertices.…

题目链接 Problem Description 速算24点相信绝大多数人都玩过.就是随机给你四张牌,包括A(1),2,3,4,5,6,7,8,9,10,J(11),Q(12),K(13).要求只用'+','-','*','/'运算符以及括号改变运算顺序,使得最终运算结果为24(每个数必须且仅能用一次).游戏很简单,但遇到无解的情况往往让人很郁闷.你的任务就是针对每一组随机产生的四张牌,判断是否有解.我们另外规定,整个计算过程中都不能出现小数. Input 每组输入数据占一行,给定四张牌. Ou…

/* 思路:http://blog.csdn.net/string_yi/article/details/12686873 hdu 1814 输出字典序最小的2-sat */ #include<stdio.h> #include<string.h> #include<math.h> #define N 16100 #define NN 210000 struct node { int v,w,next; }bian[NN*2]; int head[N],cnt,yong…