本周内:select * from wap_content where week(created_at) = week(now) 查询一天:select * from table where to_days(column_time) = to_days(now());select * from table where date(column_time) = curdate(); 查询7天:select * from table  where DATE_SUB(CURDATE(), INTERVA…

如果你要严格要求是某一年的,那可以这样 查询一天: select * from table where to_days(column_time) = to_days(now()); select * from table where date(column_time) = curdate(); 查询一周: DAY) <= date(column_time); 查询一个月: select * from table where DATE_SUB(CURDATE(), INTERVAL 1 MONTH…

select * from wap_content where week(created_at) = week(now) 如果你要严格要求是某一年的,那可以这样 查询一天: select * from table where to_days(column_time) = to_days(now());select * from table where date(column_time) = curdate(); 查询一周: select * from table where DATE_SUB(C…

本周内:select * from wap_content where week(created_at) = week(now) 查询一天:select * from table where to_days(column_time) = to_days(now());select * from table where date(column_time) = curdate(); 查询7天:select * from table  where DATE_SUB(CURDATE(), INTERVA…

mysql查询各种类型的前N条记录,将3改为N(需查询条数)即可  (select * from event_info where event_type = 1  limit 3)union all(select * from event_info where event_type = 2  limit 3)union all(select * from event_info where event_type = 3  limit 3) 原文出处:http://my.oschina.net/u/…

MySQL 查询某个数据库中所有包含数据记录的表名 有时根据实际应用需要,需要对数据进行备份. 如果一个数据库中有很多数据表,但是只想备份包含数据记录的那些表数据(空表不做数据备份). 如果通过如下SQL,逐一确认表中是否有数据,效率会很低: ) from tableN; 如何直接获取某个数据库中,所有包含数据的表名呢? 查询SQL如下: select TABLE_NAME from information_schema.TABLES ;…

SELECT HOUR(e.time)as Hour,FLOOR(MINUTE(e.time)/30) as M, COUNT(*) as Count FROM error_log e WHERE e.date = '2017-09-02' GROUP BY FLOOR(MINUTE(e.time)/30),HOUR(e.time) ORDER BY Hour(e.time); floor函数是mysql 的向下取整函数 如 floor(1.2) = 1 以下是运行结果: 要查看每小时统计,请看…

常用计算日期的函数 日 date(日期) = CURDATE() 自然周 YEARWEEK(date_format(日期,'%Y-%m-%d') , 1) = YEARWEEK(now() , 1) 月 DATE_FORMAT( 日期, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' ) 计算周的原理 MySql计算周的函数有两个,一个是YEARWEEK(date, mode)一个是WEEK(date, mode) 他们的原理都是通过计算当前日期是属于一年…

1.查询当天的数据 select * from 表名 where TO_DAYS(时间字段)=TO_DAYS(NOW()); 2.查询当周的数据 select * from 表名 where YEARWEEK(DATE_FORMAT(时间字段,'%Y-%m-%d'))=YEARWEEK(NOW()); 3.查询当月的数据 select * from 表名 where DATE_FORMAT(时间字段,'%Y%m')=DATE_FORMAT(CURDATE(),'%Y%m'); 4.查询昨天的数据…

SELECT birthday, )) + '-' + )) + '-' + )) AS datetime) AS Nbirthday FROM CRM_Customer WHERE birthday is not NULL AND (//当前时间要大于等于生日 Datediff(day, )) + '-' + )) + '-' + )) AND //当前时间要减去生日,要小于7天 Datediff(day, )) + '-' + )) + '-' + )) )…