题目: Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInter…

Insert Interval  Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9],…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInterval…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInterval…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […

Insert interval  题意简述:给定若干个数轴上的闭区间,保证互不重合且有序,要求插入一个新的区间,并返回新的区间集合,保证有序且互不重合. 只想到了一个线性的解法,所有区间端点,只要被其他区间覆盖,就是不合法的,把他们去掉后,就可以直接得到答案.设新区间为[left,right],那么,比left小的端点显然合法,比right大的端点显然也合法,left和right之间的端点显然不合法,然后判断Left和right是否合法即可.难度不大,代码有些细节需要注意. /** * Defi…

lc57 Insert Interval 仔细分析题目,发现我们只需要处理那些与插入interval重叠的interval即可,换句话说,那些end早于插入start以及start晚于插入end的interval都可以保留.我们只需要两个指针,i&j分别保存重叠interval中最早start和最晚end即可,然后将interval [i, j]插入即可 class Solution { public int[][] insert(int[][] intervals, int[] newInte…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and merge…

给出一个无重叠的按照区间起始端点排序的区间列表.在列表中插入一个新的区间,你要确保列表中的区间仍然有序且不重叠(如果有必要的话,可以合并区间).示例 1:给定区间 [1,3],[6,9],插入并合并 [2,5] 得到 [1,5],[6,9].示例 2:给定区间 [1,2],[3,5],[6,7],[8,10],[12,16],插入并合并 [4,9] 得到 [1,2],[3,10],[12,16].这是因为新的区间 [4,9] 与 [3,5],[6,7],[8,10] 重叠.详见:https://…

1. 原题链接 https://leetcode.com/problems/insert-interval/description/ 2. 题目要求 该题与上一题的区别在于,插入一个新的interval对象,将此对象与所给列表里的Interval对象进行合并. 3. 解题思路 首先遍历Interval对象列表,找到插入位置.将插入位置之前的列表中的Interval对象直接加入结果列表. 然后查找所要插入Interval对象的end属性在列表中的位置. 最后将列表中剩余的Interval对象全部加…

原题地址 遍历每个区间intervals[i]: 如果intervals[i]在newInterval的左边,且没有交集,把intervals[i]插入result 如果intervals[i]在newInterval的右边,且没有交集,如果newInterval还没插入,则将newInterval插入result,之后再插入intervals[i] 如果intervals[i]和newInterval有交集,则更新newInterval的start.end 代码: vector<Interva…

阅读了几个博客, 决定写一个简易版本; 忙着做更多题, 没有时间多考虑优化代码, 所以, 就写一个试试运气. http://blog.csdn.net/kenden23/article/details/17264441 http://blog.csdn.net/worldwindjp/article/details/21612731 Two versions are compared in the following blog: http://simpleandstupid.com/2014/1…

LeetCode中,有很多关于一组interval的问题.大体可分为两类: 1.查看是否有区间重叠: 2.合并重叠区间;  3.插入新的区间: 4. 基于interval的其他问题 [ 做题通用的关键步骤]: 1. 按照begin时间排序: 2. 判断两个相邻区间是否重叠: [假设] a. 给定的区间是半开区间 [begin, end); b. 已经按照"begin"排序. c. 当前的区间是begin, end; 要比较/合并的区间:[ intervals[i][0], interv…

56. Merge Intervals是一个无序的,需要将整体合并:57. Insert Interval是一个本身有序的且已经合并好的,需要将新的插入进这个已经合并好的然后合并成新的. 56. Merge Intervals 思路:先根据start升序排序,然后合并 static作用:https://www.cnblogs.com/songdanzju/p/7422380.html 之间写的一个较为复杂的代码 /** * Definition for an interval. * struct…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […

Insert Interval Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], in…

Description Given a non-overlapping interval list which is sorted by start point. Insert a new interval into it, make sure the list is still in order and non-overlapping (merge intervals if necessary). Example Insert (2, 5) into [(1,2), (5,9)], we ge…

Insert Interval Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], in…

题目 Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). Yo…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and merge…

Hard! 题目描述: 给出一个无重叠的 ,按照区间起始端点排序的区间列表. 在列表中插入一个新的区间,你需要确保列表中的区间仍然有序且不重叠(如果有必要的话,可以合并区间). 示例 1: 输入: intervals = [[1,3],[6,9]], newInterval = [2,5] 输出: [[1,5],[6,9]] 示例 2: 输入: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8] 输出: [[1,…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […

一天一道LeetCode系列 (一)题目 Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,…

题目: Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and mer…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […

题目: Given a collection of intervals, merge all overlapping intervals. Example 1: Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6]. Example 2: Input: [[1,4]…

1. Merge Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. /** * Definition for an interval. * struct Interval { * int start; * int end; * Interval() : start(0)…

LintCode #30. Insert Interval (Easy) LeetCode #57. Insert Interval (Hard) class Solution { public: vector<Interval> insert(vector<Interval> &intervals, Interval newInterval) { vector<Interval> v; auto it = intervals.begin(); while (i…

作者:jostree  转载请注明出处 http://www.cnblogs.com/jostree/p/4051169.html 题目链接:leetcode Insert Interval 使用模拟的方法,把需要插入的区间和每一个给定的区间进行比较,有三种情况: 1.给定区间的起点小于要插入区间的终点,并且区间还未被查入过,那么插入区间. 2.给定区间的终点大于要插入区间的起点,或者插入区间已经被插入过了,那么插入给定区间. 3.不满足以上两种情况,说明给定区间与插入区间有交集,那么把需要插入…