题目描述: Given an integer array with even length, where different numbers in this array represent different kinds of candies. Each number means one candy of the corresponding kind. You need to distribute these candies equally in number to brother and si…

Given an integer array with even length, where different numbers in this array represent different kinds of candies. Each number means one candy of the corresponding kind. You need to distribute these candies equally in number to brother and sister.…

题目要求 Given an integer array with even length, where different numbers in this array represent different kinds of candies. Each number means one candy of the corresponding kind. You need to distribute these candies equally in number to brother and sis…

题目: Given an integer array with even length, where different numbers in this array represent different kinds of candies. Each number means one candy of the corresponding kind. You need to distribute these candies equally in number to brother and sist…

有些时候,我们需要知道一个字符串中字符的位置,或者一个数组中元素的位置,这是就需要对该变量进行迭代操作. 对于数组,有两个方法indexOf和findIndex() , 需要注意的是,findIndex是数组的方法,不适用于字符串 let arr = ['a' ,'b', 'c'] let idx = arr.findIndex((item) => { return item == 'b' }) console.log(arr.indexOf('c')); console.log(idx) 对于…

题目: Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space to hold additional elements from B. The number of elements initialized in A and B are m and n respectively. 题意要把两个有序的数组合并到他们…

Given m arrays, and each array is sorted in ascending order. Now you can pick up two integers from two different arrays (each array picks one) and calculate the distance. We define the distance between two integers a and b to be their absolute differ…

如何判断一个数组中是否有重复的元素 实现判断数组中是否包含有重复的元素方法 这里用C#代码给出实例 方法一:可以新建一个hashtable利用hashtable的Contains方法进行查找 /// <summary> /// Hashtable 方法 /// </summary> /// <param name="array"></param> /// <returns></returns> public sta…

C#实现如何判断一个数组中是否有重复的元素   如何判断一个数组中是否有重复的元素 实现判断数组中是否包含有重复的元素方法 这里用C#代码给出实例 方法一:可以新建一个hashtable利用hashtable的Contains方法进行查找 按 Ctrl+C 复制代码 按 Ctrl+C 复制代码 方法二:使用for循环进行比较  需要注意的是j<=i    如果只是等于,实际上效率偏低,有重复计算可以自己摸索,有时间我画个图出来,^_^(这里感谢面试官的提醒) 1 /// <summary>…

需求:  计算一个字符串中每个字符出现的次数 思路: 通过toCharArray()拿到一个字符数组--> 遍历数组,将数组元素作为key,数值1作为value存入map容器--> 如果key重复,通过getKey()拿到value,计算value+1后存入 代码如下: import java.util.*; public class MapDemo { public static void main(String[] args) { String str = "sdnasjhdas…