Partial Sum Accepted : Submit : Time Limit : MS Memory Limit : KB Partial Sum Bobo has a integer sequence a1,a2,…,an of length n. Each time, he selects two ends ≤l<r≤n and add |∑rj=l+1aj|−C into a counter which is zero initially. He repeats the selec…
Partial Sum Accepted : 80 Submit : 353 Time Limit : 3000 MS Memory Limit : 65536 KB Partial Sum Bobo has a integer sequence a1,a2,…,an of length n . Each time, he selects two ends 0≤l<r≤n and add |∑rj=l+1aj|−C into a counter which is zero initia…
The partial sum problem 时间限制:1000 ms | 内存限制:65535 KB 难度:2 描写叙述 One day,Tom's girlfriend give him an array A which contains N integers and asked him:Can you choose some integers from the N integers and the sum of them is equal to K. 输入 There are mul…
描述 One day,Tom’s girlfriend give him an array A which contains N integers and asked him:Can you choose some integers from the N integers and the sum of them is equal to K. 输入 There are multiple test cases. Each test case contains three lines.The fir…
算法:搜索 描述 One day,Tom's girlfriend give him an array A which contains N integers and asked him:Can you choose some integers from the N integers and the sum of them is equal to K. 输入There are multiple test cases. Each test case contains three lines.The…
描述 One day,Tom’s girlfriend give him an array A which contains N integers and asked him:Can you choose some integers from the N integers and the sum of them is equal to K. 输入 There are multiple test cases. Each test ≤N≤),represents the array contains…
2017江苏省赛的E题,当时在场上看错了题目没做出来,现在补一下…… 题目链接:http://202.197.224.59/OnlineJudge2/index.php/Problem/read/id/1264(注意在上面使用G++编译的话,请使用%I64d) Time Limit : 3000 MS Memory Limit : 65536 KB Bobo has a integer sequence a1,a2,…,an of length n. Each time, he selects…
选定最多m的区间,使区间和的绝对值最大.但是左右端点不能重复选取 首先涉及到区间和的问题,就应该想到用前缀和去优化 这里对前缀和排序 然后贪心的去选取最大.次大 (比赛的时候脑子堵的很,没想出来 可惜了) #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #define ll long long int using namespace std; ll sum[1…
the algorithm of three version below is essentially the same, namely, Kadane's algorithm, which is of O(n) complexity. https://en.wikipedia.org/wiki/Maximum_subarray_problem the evolution of the implementations is to remove redundancy and do what is…
Description Given a series of n numbers a1, a2, ..., an, the partial sum of the numbers is defined as the sum of ai, ai+1, ..., aj. You are supposed to calculate how many partial sums of a given series of numbers could be divided evenly by a given nu…
谷歌路过这个专门介绍HMM及其相关算法的主页:http://rrurl.cn/vAgKhh 里面图文并茂动感十足,写得通俗易懂,可以说是介绍HMM很好的范例了.一个名为52nlp的博主(google “I Love Natural Language Processing”估计就能找到)翻译后的HMM入门介绍如下,由于原文分了很多章节,我嫌慢了还是一次性整理,长文慎入吧. 一.介绍(Introduction) 我们通常都习惯寻找一个事物在一段时间里的变化模式(规律).这些模式发生在很多领域,比如计…
SAS Annotated Output GLM 在使用SAS过程中,proc glm步输出离差平方和有4种算法,分别是SS1 SS2 SS3 SS4 下面文章介绍了其中SS3的具体计算步骤和例子. This page shows an example of analysis of variance run through a general linear model (glm) with footnotes explaining the output. The data were coll…
An Attempt to Understand Boosting Algorithm(s) WELCOME! Here you will find daily news and tutorials about R, contributed by over 573 bloggers. There are many ways tofollow us - By e-mail: On Facebook: If you are an R blogger yourself you are invited…
js像其他动态语言一样是可以写高阶函数的,所谓高阶函数是可以操作函数的函数.因为在js中函数是一个彻彻底底的对象,属于第一类公民,这提供了函数式编程的先决条件. 下面给出一个例子代码,出自一本js教程,功能是计算数组元素的平均值和标准差,先列出非函数式编程的一种写法: var data = [1,1,3,5,5]; var total = 0; for(var i = 0;i < data.length;i++) total += data[i]; var mean = tatal/data.l…
链接:https://www.icpc.camp/contests/4mYguiUR8k0GKE Partial Sum Input The input contains zero or more test cases and is terminated by end-of-file. For each test case: The first line contains three integers n, m, C. The second line contains n integers a1…
Problem set 1 // Homework 1 // Color to Greyscale Conversion //A common way to represent color images is known as RGBA - the color //is specified by how much Red, Green, and Blue is in it. //The 'A' stands for Alpha and is used for transparency; it w…