hdu 2685 I won't tell you this is about number theory 数论

【hdu 2685 I won't tell you this is about number theory 数论】的更多相关文章

hdu 2685 I won't tell you this is about number theory 数论

题目链接根据公式 \[ gcd(a^m-1, a^n-1) = a^{gcd(m, n)}-1 \] 就可以很容易的做出来了. #include <iostream> #include <vector> #include <cstdio> #include <cstring> #include <algorithm> #include <complex> #include <cmath> #include <map…

HDU 2685 I won't tell you this is about number theory

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2685 题意:求gcd(a^m - 1, a^n - 1) mod k 思路:gcd(a^m - 1, a^n - 1) = a^gcd(m, n) - 1 code: #include <stdio.h> int gcd(int a, int b) { return !b ? a : gcd(b, a%b); } int mod_pow(int a, int x, int mod) { int t…

HDU 2685 GCD推导

求$(a^n-1,a^m-1) \mod k$,自己手推,或者直接引用结论$(a^n-1,a^m-1) \equiv a^{(n,m)}-1 \mod k$ /** @Date : 2017-09-21 21:41:26 * @FileName: HDU 2685 结论定理推导.cpp * @Platform: Windows * @Author : Lweleth (SoungEarlf@gmail.com) * @Link : https://github.com/ * @Version…

HDU 1005 Number Sequence(数论)

HDU 1005 Number Sequence(数论) Problem Description: A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multipl…

hdu 2685(数论相关定理+欧几里德定理+快速取模)

I won't tell you this is about number theory Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 458 Accepted Submission(s): 142 Problem Description To think of a beautiful problem description is…

HDU 1210 Eddy's 洗牌问题（foj1062) || FOJ1050 Number lengths水

麻痹,感冒了. ------------------------------------------------感冒了的分割线------------------------------------------------ HDU 1210 也就是 FOJ 1062 http://acm.hdu.edu.cn/showproblem.php?pid=1210 http://acm.fzu.edu.cn/problem.php?pid=1062 Eddy是个ACMer,他不仅喜欢做ACM题,而且对…