HDU3191 【输出次短路条数】】的更多相关文章

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3191 How Many Paths Are There Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2128    Accepted Submission(s): 749 Problem Description   oooccc1 is…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1688 题目大意:给n个点,m条有向边.再给出起点s, 终点t.求出s到t的最短路条数+次短路条数. 思路: 1.最短路和次短路是紧密相连的,在最短路松弛操作中,当我们找到一条更短的路径,也就意味着之前的路径不再是最短路,而成为了次短路,利用这个关系可以实现状态的转移. 2.好久没写优先队列了,都忘记了加个 priority_queue, 这样才能写重载,才能排序. 注释在代码里: #include<…
Sightseeing Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1023    Accepted Submission(s): 444 Problem Description Tour operator Your Personal Holiday organises guided bus trips across the Ben…
/* 对dij的再一次理解 每个点依旧永久标记 只不过这里多搞一维 0 1 表示最短路还是次短路 然后更新次数相当于原来的两倍 更新的时候搞一下就好了 */ #include<iostream> #include<cstdio> #include<cstring> #include<queue> #include<vector> #define maxn 1010 using namespace std; ],f[maxn][],c[maxn][…
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题意 求出最短路和次短路的条数,当次短路比最短路长度小1时,输出条数之和,反之输出最短路条数. 题解  dis1[],cnt1[],dis2[],cnt2[] 分别表示最短路的长度和条数,次短路的长度和条数.  当当前距离小于当前点最短路长度的时候,更新二者长度和条数.  当当前距离等于当前点最短路长度的时候,更新最短路条数.  当当前距离小于当前点次短路长度的时候,更新次短路的长度和条数.  当当前距离等于当前点次短路长度的时候,更新次短路的条数.  push进队列的时候要标注push进去的是…
Marriage Match IV 题目链接: http://acm.hust.edu.cn/vjudge/contest/122685#problem/Q Description Do not sincere non-interference. Like that show, now starvae also take part in a show, but it take place between city A and B. Starvae is in city A and girls a…
Hibernate数据库操作类(eg:TexDAO.java) /* * queryString HQL语句,first开始条数, max输出条数 ,norder排序 * 例: List lis = dao.findOther("from Tex",2,10," uid desc "); */ public List findOther(String queryString, int first, int max, String norder) { StringBu…
http://poj.org/problem?id=3463 Sightseeing Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 7252   Accepted: 2581 Description Tour operator Your Personal Holiday organises guided bus trips across the Benelux. Every day the bus moves from…