An Easy Task Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17062    Accepted Submission(s): 10902 Problem Description Ignatius was born in a leap year, so he want to know when he could hold h…

题解:枚举即可…… #include <cstdio> int main(){ int now,y,n,T,count; scanf("%d",&T); while(T--){ scanf("%d%d",&y,&n); for(now=y;;now++){ if((now%4==0&&now%100!=0)||(now%400)==0)n--; if(!n){printf("%d\n",now)…

水题,如题. #include <stdio.h> #define chk(Y) (Y%4==0 && Y%100!=0) || Y%400==0 int main() { int case_n; int i, y, n; scanf("%d", &case_n); while (case_n--) { scanf("%d %d", &y, &n); i = ; ) { if ( chk(y) ) i++; if…

Problem Description Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him? Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap y…

http://acm.hdu.edu.cn/game/entry/problem/list.php?chapterid=1§ionid=2 1.2.5 #include<stdio.h> /* 题意:找闰年. if((i%4==0 && i%100!=0) || i%400==0)count++; 3 2005 25 1855 12 2004 10000 2108 1904 43236 */ int main() { int t,y,n; int i,count=0; whil…

题目1006:ZOJ问题 时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:15725 解决:2647 题目描写叙述: 对给定的字符串(仅仅包括'z','o','j'三种字符),推断他能否AC. 是否AC的规则例如以下: 1. zoj能AC: 2. 若字符串形式为xzojx,则也能AC.当中x能够是N个'o' 或者为空: 3. 若azbjc 能AC,则azbojac也能AC.当中a,b,c为N个'o'或者为空: 输入: 输入包括多组測试用例,每行有一个仅仅包括'z','o','j'三种字…

B. An Easy Task Time Limit: 1000ms Case Time Limit: 1000ms Memory Limit: 65536KB 64-bit integer IO format: %lld      Java class name: Main Submit Status PID: 35999 Font Size:  +   - You are given an easy task by your supervisor -- to find the best va…

A. Appleman and Easy Task time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Toastman came up with a very easy task. He gives it to Appleman, but Appleman doesn't know how to solve it. Can you…

HDU 2096 /* HDU 2096 小明A+B --- 水题 */ #include <cstdio> int main() { #ifdef _LOCAL freopen("D:\\input.txt", "r", stdin); #endif int a, b, c, n; scanf("%d", &n); while (n--){ scanf("%d%d", &a, &b); a…

An Easy Task Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 1   Accepted Submission(s) : 1 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Ignatius was born in a lea…