POJ3273-Monthly Expense-二分答案】的更多相关文章

题目链接:http://poj.org/problem?id=3273   Monthly Expense Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 29231   Accepted: 11104 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run th…
Monthly Expense Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 36628 Accepted: 13620 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and reco…
[POJ 3273] Monthly Expense (二分) 一个农民有块地 他列了个计划表 每天要花多少钱管理 但他想用m个月来管理 就想把这个计划表切割成m个月来完毕 想知道每一个月最少花费多少 每一个月的花费是这个月的花费加和 必须按计划表的顺序来 全部天中花费中最大花费作为下界 全部花费加和作为上界 二分上下界间的花费可能 找出最少每月花费就可以 代码例如以下: #include <iostream> #include <cstdio> using namespace s…
POJ 3273 Monthly Expense二分查找(最大值最小化问题) 题目:Monthly Expense Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and recorded the exact amount of money (1 ≤ mon…
链接:http://poj.org/problem?id=3273 题意:FJ想把n天分成m组,每组是连续的,同一组的花费加起来算,求所分组情况中最高花费的最低值 思路:二分答案.二分整数范围内的花费,每次去check一下,check的过程贪心处理即可. AC代码: #include<iostream> #include<stack> #include<vector> #include<algorithm> #include<cmath> usi…
Monthly Expense Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 17982 Accepted: 7190 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and recor…
POJ 3273 Monthly Expense 此题与POJ3258有点类似,一开始把判断条件写错了,wa了两次,二分查找可以有以下两种: ){ mid=(lb+ub)/; if(C(mid)<=m) ub=mid; ; //此时下限过小 } out(ub);//out(lb) 我一开始是写的下面这种,下面这种要单独判断lb和ub的值,因为用下面这种判断lb,ub都可能成立 ){ mid=(lb+ub)/; if(C(mid)<=m) ub=mid; else lb=mid; } if(C(…
Monthly Expense Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 25959   Accepted: 10021 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and…
Monthly Expense Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 19207   Accepted: 7630 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and r…
/* Monthly Expense Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10757 Accepted: 4390 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and re…
Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and recorded the exact amount of money (1 ≤ moneyi ≤ 10,000) that he will need to spend each day over the…
题目:http://poj.org/problem?id=3273 二分枚举,据说是经典题,看了题解才做的,暂时还没有完全理解.. #include <stdio.h> #include <string.h> int n, m; ]; bool judge(int x) { , cnt = ; ; i < n; i++) { if(money + a[i] <= x) money += a[i]; else { money = a[i]; cnt++; } } if(c…
Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11196   Accepted: 4587 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and recorded the exac…
https://vjudge.net/problem/POJ-3273 认真审题,代码仔细!!ans的初值应该是1 #include<iostream> #include<cstdio> #include<queue> #include<cstring> #include<algorithm> #include<cmath> #include<map> #define lson l, m, rt<<1 #def…
查看原题 边界,就是边界和思维,怎么有效的判断中间值是大了还是小了,以及准确的找到边界!一个<写成<=就前功尽弃,还特别难找到错误! #include <cstdio> #include <algorithm> ; int N, M; int A[maxN]; using namespace std; int main(void) { == scanf("%d%d", &N, &M)) { , l = , m, sum, cnt, i…
//最大值最小 //天数的a[i]值是固定的 不能改变顺序 # include <algorithm> # include <string.h> # include <stdio.h> using namespace std; int n,m; int a[100010]; int judge(int x) { int ans=1;//分成了几组 int tmp=0; for(int i=0;i<n;i++) { tmp+=a[i]; if(tmp>x) {…
                                                                            POJ-3273                                                                                 Monthly Expense Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 10557  …
P2884 [USACO07MAR]每月的费用Monthly Expense 二分经典题 二分每个段的限制花费,顺便统计下最大段 注意可以分空段 #include<iostream> #include<cstring> #include<cstdio> using namespace std; int max(int &a,int &b){return a>b?a:b;} #define N 100001 int a[N],n,m,ans=2e9;…
直接二分答案然后判断. ----------------------------------------------------------------------------- #include<cstdio> #include<cstring> #include<algorithm> #include<iostream>   #define rep( i , n ) for( int i = 0 ;  i < n ; ++i ) #define c…
题意:给出n天的花费,需要将这n天的花费分成m组,使得每份的和尽量小,求出这个最小的和 看题目看了好久不懂题意,最后还是看了题解 二分答案,上界为这n天花费的总和,下界为这n天里面花费最多的那一天 如果mid>=m,说明mid偏小,l=mid+1, 如果mid<m,说明mid偏大,r=mid, #include<iostream> #include<cstdio> #include<cstring> #include <cmath> #inclu…
Monthly Expense Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 14158   Accepted: 5697 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and r…
Monthly Expense 直接上中文 Descriptions 给你一个长度为N的序列,现在要让你把他们切割成M份(所以每一份都是连续的),然后每一份都有一个和sum[i],其中最大的一个是maxSum = max(sum[i]),问这个最大值最小是多少? 输入 多组输入输出每组数据第一行是2个整数N,M(1<=M<=N<=100000),接着是N行,每行一个整数vi,表示这个序列. 输出 每组数据输出一行一个数,为这个最大值最小是多少 输入样例 7 510040030010050…
题目链接:http://poj.org/problem?id=3273 题目大意:给出一个有n个数据的数组,将其分为连续的m份,找到一种分法,是的m份中最大一份总和最小 解题思路: 直接在答案的区间内二分查找,找到符合条件的答案. #include <cstdio> int main() { int n, m; while (scanf("%d %d", &n, &m) != EOF) { int i, j; ]; , right = ; ; i <…
忘开long long了居然没WA 二分答案,枚举判断看最后需要的月份数是否小于等于要求的即可 #include<iostream> #include<cstdio> using namespace std; const int N=100005; int n,m,a[N],l,r,ans; int read() { int r=0,f=1; char p=getchar(); while(p>'9'||p<'0') { if(p=='-') f=-1; p=getch…
1639: [Usaco2007 Mar]Monthly Expense 月度开支 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 593  Solved: 295[Submit][Status] Description Farmer John是一个令人惊讶的会计学天才,他已经明白了他可能会花光他的钱,这些钱本来是要维持农场每个月的正常运转的.他已经计算了他以后N(1<=N<=100,000)个工作日中每一天的花费moneyi(1<=money…
Monthly Expense 题目大意:不废话,最小化最大值 还是直接套模板,不过这次要注意,是最小化最大值,而不是最大化最小值,判断的时候要注意 联动3258 #include <iostream> #include <functional> #include <algorithm> using namespace std; ]; void Search(const int, const int, const int); bool C(const int, cons…
1639: [Usaco2007 Mar]Monthly Expense 月度开支 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 529  Solved: 269[Submit][Status] Description Farmer John是一个令人惊讶的会计学天才,他已经明白了他可能会花光他的钱,这些钱本来是要维持农场每个月的正常运转的.他已经计算了他以后N(1<=N<=100,000)个工作日中每一天的花费moneyi(1<=money…
BZOJ1650-[Usaco2006 Dec]River Hopscotch 跳石子 [题目大意] 数轴上有n个石子,第i个石头的坐标为Di,现在要从0跳到L,每次条都从一个石子跳到相邻的下一个石子.现在FJ允许你移走M个石子,问移走这M个石子后,相邻两个石子距离的最小值的最大值是多少. *0和L也是两块石头! [思路] 二分最小值检验即可.二分都是套路,然而我写错了,烧 杯 把ub敲成了l,忘记了范围其实是[lb,ub)QAQ 检验部分的套路:last记录上一次跳到的石头,只要当前石头和上一…
1639: [Usaco2007 Mar]Monthly Expense 月度开支 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 700  Solved: 347[Submit][Status][Discuss] Description Farmer John是一个令人惊讶的会计学天才,他已经明白了他可能会花光他的钱,这些钱本来是要维持农场每个月的正常运转的.他已经计算了他以后N(1<=N<=100,000)个工作日中每一天的花费moneyi(1&…
题目传送门 /* 题意:分成m个集合,使最大的集合值(求和)最小 二分搜索:二分集合大小,判断能否有m个集合. */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> using namespace std; ; const int INF = 0x3f3f3f3f; int a[MAXN]; int n, m; bool check(int tot) { ,…