四边形优化dp】的更多相关文章

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2829 题目大意:有一段铁路有n个站,每个站可以往其他站运送粮草,现在要炸掉m条路使得粮草补给最小,粮草补给的公式是将每个站能收到的粮草的总和. 4----5-----1-----2 粮草总和为4*5 + 4*1 + 4*2 + 5*1 + 5*2 + 1*2 = 49. 4----5       1-----2 粮草总和为4*5 + 1*2 = 22. 4      5-----1------2 粮…
原题链接:http://acm.hdu.edu.cn/showproblem.php?pid=3516 题意: 大概就是给你个下凸包的左侧,然后让你用平行于坐标轴的线段构造一棵树,并且这棵树的总曼哈顿距离最短 题解: 很容易得到转移方程: $$dp[i][j]=min \{ dp[i][k-1]+dp[k][j] + dis(uni(i,k-1),uni(k,j))\}$$ 其中$dp[i][j]$表示从$i$到$j$的最优解,$dis(i,j)$表示$i$和$j$之间的曼哈顿距离,$uni(i…
Lawrence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1701    Accepted Submission(s): 737 Problem Description T. E. Lawrence was a controversial figure during World War I. He was a British o…
理解: http://blog.renren.com/share/263498909/1064362501 http://www.cnblogs.com/ronaflx/archive/2011/03/30/1999764.html http://yomean.blog.163.com/blog/static/189420225201272864127683/ http://www.cnblogs.com/zxndgv/archive/2011/08/02/2125242.html 题目总结:…
题目传送门 f[i] = min(f[j] + val(i,j); 其中val(i,j) 满足 四边形dp策略. 代码: #include<bits/stdc++.h> using namespace std; #define Fopen freopen("_in.txt","r",stdin); freopen("_out.txt","w",stdout); #define LL long long #defin…
Breaking Strings Time Limit: 2 Seconds        Memory Limit: 65536 KB A certain string-processing language allows the programmer to break a string into two pieces. Since this involves copying the old string, it costs n units of time to break a string…
前几天做多校,知道了这世界上存在dp的优化这样的说法,了解了四边形优化dp,所以今天顺带做一道典型的斜率优化,在百度打斜率优化dp,首先弹出来的就是下面这个网址:http://www.cnblogs.com/ka200812/archive/2012/08/03/2621345.html 上面讲的很详细,但是实际上有些地方貌似是不小心写错了,所以我也来复述一下感悟一下收获. 首先题意是比较明确的,如果我们定义dp[i]为打印到第i个字符时的最小花费的话,显然有下面的转移: dp[i]=dp[j]…
T. E. Lawrence was a controversial figure during World War I. He was a British officer who served in the Arabian theater and led a group of Arab nationals in guerilla strikes against the Ottoman Empire. His primary targets were the railroads. A highl…
题目链接 洛谷P1912[原题,需输出方案] BZOJ1563[无SPJ,只需输出结果] 题解 四边形不等式 什么是四边形不等式? 一个定义域在整数上的函数\(val(i,j)\),满足对\(\forall a \le b \le c \le d\)有 \[val(a,d) + val(b,c) \ge val(a,c) + val(b,d)\] 那么我们称函数\(val(i,j)\)满足四边形不等式 一般地,当我们需要证明一个函数\(val(i,j)\)满足四边形不等式时,只需证对于\(\fo…
Monkey Party Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 1699    Accepted Submission(s): 769 Problem Description Far away from our world, there is a banana forest. And many lovely monkeys l…