PAT A1114 Family Property】的更多相关文章

用并查集处理每个家庭的信息,注意标记~ #include<bits/stdc++.h> using namespace std; ; bool visit[maxn]={false}; int N; struct node { int id; ]; double num; double area; }Node[maxn]; struct family { int id; double num; double area; int renshu; }f[maxn]; int father[maxn…
This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info under his/her own name, we need to know the size of each family, and the average area and number of sets of…
1114 Family Property (25 分) This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info under his/her own name, we need to know the size of each family, and the average…
This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info under his/her own name, we need to know the size of each family, and the average area and number of sets of…
1114 Family Property(25 分) This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info under his/her own name, we need to know the size of each family, and the average…
This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info under his/her own name, we need to know the size of each family, and the average area and number of sets of…
Source: PAT (Advanced Level) Practice Reference: [1]胡凡,曾磊.算法笔记[M].机械工业出版社.2016.7 Outline: 基础数据结构: 线性表:栈,队列,链表,顺序表 树:二叉树的建立,二叉树的遍历,完全二叉树,二叉查找树,平衡二叉树,堆,哈夫曼树 图:图的存储和遍历 经典高级算法: 深度优先搜索,广度优点搜索,回溯剪枝 贪心,并查集,哈希映射 最短路径(只考察过单源),拓扑排序(18年9月第一次涉及相关概念,未正式考过),关键路径(未…
Source: PAT A1114 Family Property (25 分) Description: This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info under his/her own name, we need to know the size of ea…
专题一  字符串处理 A1001 Format(20) #include<cstdio> int main () { ]; int a,b,sum; scanf ("%d %d",&a,&b); sum=a+b; ) { printf ("-"); sum=-sum; } ; ) { s[top++]=; } ) { s[top++]=sum%; sum/=; } ;i>=;i--) { printf ("%d"…
PAT甲级1114. Family Property 题意: 这一次,你应该帮我们收集家族财产的数据.鉴于每个人的家庭成员和他/她自己的名字的房地产(房产)信息,我们需要知道每个家庭的规模,以及他们的房地产的平均面积和数量. 输入规格: 每个输入文件包含一个测试用例.对于每种情况, 第一行给出正整数N(<= 1000).然后N行跟随,每个给出一个拥有庄园的人的信息,格式如下: ID父亲母亲k Child1 ... Childk M_estate Area 其中ID是每个人唯一的4位数识别号码;父…