CSU 1968 Permutation Descent Counts】的更多相关文章

http://acm.csu.edu.cn/csuoj/problemset/problem?pid=1968 题意:对于任一种N的排列A,定义它的E值为序列中满足A[i]>A[i+1]的数的个数.给定N和K(K<=N<=1000),问N的排列中E值为K的个数. 思路: 这道题目和杭电的3664非常像. d[i][j]表示分析到i这个数时的E值为j的个数. 那么如何计算出d[i][j]呢?得根据d[i-1][j]和d[i-1][j-1]递推出来. ①首先考虑d[i-1][j](此时不改变…
1968: Permutation Descent Counts Submit Page   Summary   Time Limit: 1 Sec     Memory Limit: 128 Mb     Submitted: 123     Solved: 96 Description Given a positive integer, N, a permutation of order N is a one-to-one (and thus onto) function from the…
首先看一下题目 B. Permutation Game time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output n children are standing in a circle and playing a game. Children's numbers in clockwise order form a permutation …
Given two strings s1 and s2, write a function to return true if s2 contains the permutation of s1. In other words, one of the first string's permutations is the substring of the second string. Example 1: Input:s1 = "ab" s2 = "eidbaooo"…
[抄题]: Given two strings s1 and s2, write a function to return true if s2 contains the permutation of s1. In other words, one of the first string's permutations is the substring of the second string. Example 1: Input:s1 = "ab" s2 = "eidbaooo…
https://blog.csdn.net/u012328159/article/details/80252012 我们在训练神经网络模型时,最常用的就是梯度下降,这篇博客主要介绍下几种梯度下降的变种(mini-batch gradient descent和stochastic gradient descent),关于Batch gradient descent(批梯度下降,BGD)就不细说了(一次迭代训练所有样本),因为这个大家都很熟悉,通常接触梯队下降后用的都是这个.这里主要介绍Mini-b…
Discription John likes playing the game Permutation Jumping. First he writes down a permutation A of the first n numbers. Then, he chooses any cell to start on. If he is currently at cell x and hasnt visited the cell A[x], he jumps to cell A[x]. He k…
Given two strings s1 and s2, write a function to return true if s2 contains the permutation of s1. In other words, one of the first string's permutations is the substring of the second string. Example 1: Input:s1 = "ab" s2 = "eidbaooo"…
The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…
Given a string s, return all the palindromic permutations (without duplicates) of it. Return an empty list if no palindromic permutation could be form. For example: Given s = "aabb", return ["abba", "baab"]. Given s = "a…