977. Squares of a Sorted Array (Easy)# Given an array of integers A sorted in non-decreasing order, return an array of the squares of each number, also in sorted non-decreasing order. Example 1: Input: [-4,-1,0,3,10] Output: [0,1,9,16,100] Example 2:…

LeetCode:Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, other…

LeetCode:Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constan…

Search in Rotated Sorted Array II Follow up for "LeetCode: Search in Rotated Sorted Array 解题报告":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the arr…

题目 977. Squares of a Sorted Array Given an array of integers A sorted in non-decreasing order, return an array of the squares of each number, also in sorted non-decreasing order. Example 1: Input: [-4,-1,0,3,10] Output: [0,1,9,16,100] Example 2: Inpu…

problem 977. Squares of a Sorted Array solution: class Solution { public: vector<int> sortedSquares(vector<int>& A) { for(auto &a:A) a *=a; sort(A.begin(), A.end()); return A; } }; 参考1. Leetcode_easy_977. Squares of a Sorted Array; 完…

Algorithm [leetcode]657. Robot Return to Origin https://leetcode.com/problems/robot-return-to-origin/ 1)problem There is a robot starting at position (0, 0), the origin, on a 2D plane. Given a sequence of its moves, judge if this robot ends up at (0,…

problem 657. Robot Return to Origin 题意: solution1: class Solution { public: bool judgeCircle(string moves) { , cnt2 = ; for(auto move:moves) { if(move == 'L') cnt1++; else if(move=='R') cnt1--; else if(move=='U') cnt2++; else if(move=='D') cnt2--; }…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 这道是之前那道Search in Rotated Sorted Array 在旋转有序数组…

Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3]. 这道题是之前那道Remove Duplicates from Sorted Array 有序数组中…