Inna and Choose Options Time Limit: 1000ms Memory Limit: 262144KB This problem will be judged on CodeForces. Original ID: 400A64-bit integer IO format: %I64d      Java class name: (Any)   There always is something to choose from! And now, instead of…

A. Inna and Choose Options time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output There always is something to choose from! And now, instead of "Noughts and Crosses", Inna choose a very unusu…

A. Inna and Choose Options time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output There always is something to choose from! And now, instead of "Noughts and Crosses", Inna choose a very unusu…

A. Inna and Choose Options time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output There always is something to choose from! And now, instead of "Noughts and Crosses", Inna choose a very unusu…

#include <iostream> #include <string> #include <vector> using namespace std; ; ,,,,,}; int main(){ int t; cin >> t; ; i < t; ++ i ){ string character; cin >> character; vector<int> result; ; j < num ; ++ j){ /a; ,…

Inna and Choose Options Crawling in process... Crawling failed Time Limit:1000MS     Memory Limit:262144KB     64bit IO Format:%I64d & %I64u Submit Status Description There always is something to choose from! And now, instead of "Noughts and Cros…

题目描述: Inna and Nine time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have m…

题目链接:http://codeforces.com/problemset/problem/374/A 题目意思:给出一个 n 行  m 列 的棋盘,要将放置在坐标点为(i, j)的 candy 移动到四个角落(1,1),(1,m),(n, 1),(n, m) 中的其中一个.假设当前在位置(x, y),规定每次移动遵循,(x+a, y+b) . (x+a, y-b). (x-a, y+b).(x-a, y-b).求最小的移动次数. 求出 (i, j) 到每个角落的距离diff_x, diff_y…

原题地址:http://codeforces.com/contest/374/problem/A 好久没写题目总结了,最近状态十分不好,无论是写程序还是写作业还是精神面貌……NOIP挂了之后总觉得缺乏动力精神难以集中……CF做的也是一塌糊涂,各种pretest passed + fail system test,该拿下的总是拿不下,都掉成Specialist了,也不知是什么原因,一点点尽力调整吧这是道水题,本来Div2的第一题就没什么好总结的,但是这道题为整场比赛创造了无数Hack得分(不得不吐…

题目链接:http://codeforces.com/problemset/problem/499/A 题目意思:有两种按钮:1.如果当前观看的时间是 t,player 可以自动处理下一分钟,姑且理解为跳到t+1:  2.直接跳过 x 分钟,如果player在第 t 分钟,则可以跳到 t+x 分钟.问恰好可以看完 n 部电影的最少观看时间.观看一部电影(假如为第 i 部,起始时间为 li, 结束时间为 ri)表示 li, li+1, li+2, ..., ri-1, ri 的时间都要覆盖到. 一…