解题思路 用两个栈分别存字符和数字. 顺序读入字符,处理方式分为字符和数字两种. 处理字符分为')'和非')'两种. 处理数字需要读取字符栈栈顶,分为'+'.'-'和非'+'.'-'. 代码 class Solution { public: stack <int> st;//数字栈 stack <char> cst;//符号栈 void solveNum(int n){ //如果碰到加减,将上一个数字取出来,做运算之后放入栈中 if(st.size() &&cst.…

Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that the given ex…

Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negativeintegers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. Example 1: Input: "3+2*2" Ou…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression is…

▶ 两个四则表达式运算的题目,第 770 题 Basic Calculator IV 带符号计算不会做 Orz,第 772 题 Basic Calculator III 要收费 Orz. ▶ 自己的全能版代码,28 ms,采用表达式中缀转后缀,然后利用栈来计算.支持加减乘除幂模,一模一样的代码刷掉了这两题,就是效率比较低,28 ms class Solution { public: int calculate(string s)//计算器,输入表达式,输出计算结果 { string out; m…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . Example 1: Input: "1 + 1" Output: 2 Exa…

978. Basic Calculator https://www.lintcode.com/problem/basic-calculator/description public class Solution { /** * @param s: the given expression * @return: the result of expression */ public int calculate(String s) { // Write your code here Stack<Int…

例如:3+2*6-2 先定义两个栈,一个为数值栈,一个为运算符栈: stack.go package stack import ( "errors" "fmt" ) type Stack struct { MaxTop int //栈最大可以存放的数量 Top int //栈顶 Arr []int //模拟栈 } func (s *Stack) Push(val int) (err error) { //先判断栈是否满了 { fmt.Println("栈满…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression is…

题目:https://leetcode.com/problems/basic-calculator/ Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty sp…

本博客介绍leetcode上的一道不难,但是比较经典的算法题. 题目如下: Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You ma…

题目 Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression…

Basic Calculator II 题目 思路 和这个一样:Basic Calculator I 代码 class ExpressionTransformation { public: string trans_to_postfix_expression_to_s(string); // 将得到的表达式转化为后缀表达式 long long int calculate_from_postfix_expression(); // 依据后缀表达式计算值 private: vector<string…

Basic Calculator I Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the g…

一.Basic Calculator Total Accepted: 18480 Total Submissions: 94750 Difficulty: Medium Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, …

1. 问题描述 Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that the…

Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, /operators and empty spaces . The integer division should truncate toward zero. Example 1: Input: "3+2*2" Ou…

Basic Calculator I Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the g…

2018-09-27 22:02:36 一.Basic Calculator II 问题描述: 问题求解: sign用来保存前一个符号,用num来记录数字,如果碰到一个符号或者到达结尾,则需要进行入栈操作,这个时候需要结合符号进行相应的运算. public int calculate(String s) { if (s == null || s.length() == 0) return 0; int res = 0; Stack<Integer> stack = new Stack<&…

Basic Calculator II Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assu…

Basic Calculator Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the giv…

Description: Implement a basic calculator to evaluate a simple expression string. The expression string contains only non-negative integers, +, -, *, / operators and empty spaces . The integer division should truncate toward zero. You may assume that…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression is…

227. 基本计算器 II 227. Basic Calculator II 题目描述 实现一个基本的计算器来计算一个简单的字符串表达式的值. 字符串表达式仅包含非负整数,+,-,*,/ 四种运算符和空格.整数除法仅保留整数部分. LeetCode227. Basic Calculator II中等 示例 1: 输入: "3+2*2" 输出: 7 示例 2: 输入: " 3/2 " 输出: 1 示例 3: 输入: " 3+5 / 2 " 输出:…

题目如下: Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . The expression string contains only no…

Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces . You may assume that the given expression is…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 栈 参考资料 日期 题目地址:https://leetcode.com/problems/basic-calculator/description/ 题目描述 Implement a basic calculator to evaluate a simple expression string. The expression string may c…

[LeetCode]227. Basic Calculator II 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/basic-calculator-ii/description/ 题目描述: Implement a basic calculator to evaluate a simple exp…

Basic Calculator Implement a basic calculator to evaluate a simple expression string. The expression string may contain open ( and closing parentheses ), the plus + or minus sign -, non-negative integers and empty spaces ``. Example 1: Input: "1 + 1&…

最近在看<算法>这本书,正好看到一个计算表达式的问题,于是就打算写一下,也正好熟悉一下Java集合框架的使用,大致测试了一下,没啥问题. import java.util.*; /* * * 用来计算表达式 * for example: 1+2*3*(4+3*1)-3*1+2+3/1; * (1+2*2-2*1*3*(1-1))*(1-2+3*(4+0)); * 注意点: * 2.输入的表达书不能还有空格,括号必须匹配 * 基本思想: * 1.建立操作数栈以及操作符栈 * 2.先去括号,每次遇…