题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4720 题目大意:给你四个点,用前三个点绘制一个最小的圆,而这三个点必须在圆上或者在圆内,判断最一个点如果在圆外则是安全的,否则是危险的. 解题思路:我是先借用了别人的模板求三个点组成的最小的圆的圆心以及半径,就列出了圆的标准方程,将第四个点代入其中,则即可以判断此点是否在圆上还是圆外. AC代码: #include <iostream> #include <cstdio> #inclu…
Naive and Silly Muggles Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 228 Accepted Submission(s): 163 Problem Description Three wizards are doing a experiment. To avoid from bothering, a special…
Naive and Silly Muggles Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 24    Accepted Submission(s): 17 Problem Description Three wizards are doing a experiment. To avoid from bothering, a spec…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4720 解题报告:给出一个三角形的三个顶点坐标,要求用一个最小的圆将这个三个点都包含在内,另外输入一个点,问这个点是否在这个圆的圆外,如果在圆外,输出Safe,否则输出Danger. 现在的主要目的其实就是求这个最小的三角形的圆心坐标,很显然,当这个三角形是锐角三角形的时候,这个最小的圆就是这个锐角三角型的外接圆,否则就是以这个三角形最长的那条边的中点为圆心,以这条边的一半为半径的圆. #includ…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4716 题目大意不用解释了吧,看案例就能明白 #include<cstdio> #include <iostream> using namespace std; int main() { int t,n; scanf("%d",&t); ]="*------------*"; ]="|............|"; ]=…
题目传送门 /* 题意:给三个点求它们的外接圆,判断一个点是否在园内 计算几何:我用重心当圆心竟然AC了,数据真水:) 正解以后补充,http://www.cnblogs.com/kuangbin/archive/2013/09/11/3315055.html */ #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <string…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4727 题目大意:队列里所有人进行报数,要找出报错的那个人 思路:,只要找出序列中与钱一个人的数字差不是1的人即可,但是要注意的是这些人是从一个队列中间截取下来的,所以很有可能第一个人就报错了,一开始没有考虑这种状况所以出错了 #include<cstdio> #include <iostream> using namespace std; int main() { int t,n,an…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4722 题目大意:给定一个区间,求区间中有多少个满足每位上的数的和是10的倍数. 解题思路:先打表暴力求出前200项符合条件的个数,然后再找规律. 0~9    0    1个 10~19  9   1个 20~-29  18  1个 0~100         10个 0~200         20个 基本规律:r/10-(l-1)/10;只需要找两端点是否在范围内即可 #include<cstd…
Problem Description Three wizards are doing a experiment. To avoid from bothering, a special magic is set around them. The magic forms a circle, which covers those three wizards, in other words, all of them are inside or on the border of the circle.…
Naive and Silly Muggles Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 137    Accepted Submission(s): 94 Problem Description Three wizards are doing a experiment. To avoid from bothering, a spe…