一句话思路:找最大的元素.没有target? 一刷报错: 一定要用二分,否则复杂度不是最优. 判断条件是nums[mid] < nums[mid + 1],还是基于中位数比较的原理.不是nums[start] < nums[start + 1].(代码不一样都没看出来,太粗心了) 总结:用二分法往大的一边走,缩小到最后的小区间,比较一下两头就行了. class Solution { /** * @param A: An integers array. * @return: return any…

A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…

A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…

A peak element is an element that is greater than its neighbors. Given an input array nums, where nums[i] ≠ nums[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the pea…

Status: AcceptedRuntime: 9 ms 题意:给一个数组,用Vector容器装的,要求找到一个临时最高点,可以假设有num[-1]和num[n]两个元素,都是无穷小,那么当只有一个元素时,该元素就是最大的了.当然你也可以找最大值,二分法复杂度O(logn).我的想法是找临时最高点,从左到右,理想情况下,从num[0]之后会值逐渐增大,只要遇到一个比前一元素小的,就找到了.复杂度O(n),这个最大值可能是num[n-1]. 代码: class Solution { public…

Leetcode之二分法专题-162. 寻找峰值(Find Peak Element) 峰值元素是指其值大于左右相邻值的元素. 给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引. 数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可. 你可以假设 nums[-1] = nums[n] = -∞. 示例 1: 输入: nums = [1,2,3,1] 输出: 2 解释: 3 是峰值元素,你的函数应该返回其索引 2. 示例 2: 输入:…

A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…

162. 寻找峰值 162. Find Peak Element 题目描述 峰值元素是指其值大于左右相邻值的元素. 给定一个输入数组 nums,其中 nums[i] ≠ nums[i+1],找到峰值元素并返回其索引. 数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可. 你可以假设 nums[-1] = nums[n] = -∞. 每日一算法2019/6/1Day 29LeetCode162. Find Peak Element 示例 1: 输入: nums = [1,2,3,1]…

There is an integer array which has the following features: The numbers in adjacent positions are different. A[0] < A[1] && A[A.length - 2] > A[A.length - 1]. We define a position P is a peek if: A[P] > A[P-1] && A[P] > A[P+1]…

A peak element is an element that is greater than its neighbors. Given an input array where num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fi…