hdu5860 Death Sequence】的更多相关文章

这题一开始写的线段数是从中间开始查找 k个 导致是nlogn 每次查找应该都是从头找每次找的个数不同就好了 还有一种递推的写法我放下面了 #include<bits/stdc++.h> using namespace std; typedef long long ll; const int MAXN = 3e6+5; const int MOD = 1e9+7; int N,K,Q; int ans[MAXN]; int turn[MAXN]; int dp[MAXN]; int a[MAXN…
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原题链接 Problem Description You may heard of the Joseph Problem, the story comes from a Jewish historian living in 1st century. He and his 40 comrade soldiers were trapped in a cave, the exit of which was blocked by Romans. They chose suicide over captu…
HDU 5860 Death Sequence(递推) 题目链接http://acm.split.hdu.edu.cn/showproblem.php?pid=5860 Description You may heard of the Joseph Problem, the story comes from a Jewish historian living in 1st century. He and his 40 comrade soldiers were trapped in a cave…
Problem Description You may heard of the Joseph Problem, the story comes from a Jewish historian living in 1st century. He and his 40 comrade soldiers were trapped in a cave, the exit of which was blocked by Romans. They chose suicide over capture an…
用线段树可以算出序列.然后o(1)询问. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<vector> #include<map> #include<set> #include&l…
题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=5860 题目大意:给你n个人排成一列编号,每次杀第一个人第i×k+1个人一直杀到没的杀.然后剩下的人重新编号从1-剩余的人数.按照上面的方式杀.问第几次杀的是谁. 分析 一轮过后和原来问题比只是人的编号发生变化,故可以转化为子问题求解,不妨设这n个人的编号是0~n-1,对于第i个人,如果i%k=0,那么这个人一定是第一轮出列的第i/k+1个人:如果i%k!=0,那么这个人下一轮的编号就是i…
Problem Death Sequence 题目大意 排成一行的约瑟夫问题. n个人排成一行,从第一个人开始,每个k个人报数,报到数的人被杀死,剩下的人重新排成一行再报数. 一共q个询问,每次询问第qi个死的人是谁. n <= 3000000 , q <= 1000000 , k>=1 . 解题分析 显然每一轮游戏可以看做是一个子问题. 假设编号为0~n-1,若某轮中某人的编号为i,如果i被k整除则被杀,否则在下轮中编号为i-i/k-1. dp[i]表示编号为i的人可以存活几轮,那么d…
solved 7/11 2016 Multi-University Training Contest 10 题解链接 分类讨论 1001 Median(BH) 题意: 有长度为n排好序的序列,给两段子序列[l1,r1],[l2,r2]构成新的序列,问中间的数字. 思路: 根据不同情况分类讨论即可.时间复杂度O(1). 代码: #include <bits/stdc++.h> const int N = 1e5 + 5; int a[N]; int n, m; int l1, r1, l2, r…
转载:https://www.linux.com/learn/linux-career-center/44184-the-kernel-newbie-corner-kernel-debugging-with-proc-qsequenceq-files-part-3 Finally, after two installments of the basics of debugging with sequence files, we're going to finish off by demonstr…
Thermal Death of the Universe Time Limit: 10 Seconds                                     Memory Limit: 32768 KB                             Johnie has recently learned about the thermal death concept.  Given that the Global Entropy always increases,…
oracle创建序列化: CREATE SEQUENCE seq_itv_collection            INCREMENT BY 1  -- 每次加几个              START WITH 1399       -- 从1开始计数              NOMAXVALUE        -- 不设置最大值              NOCYCLE               -- 一直累加,不循环              CACHE 10; oracle修改序列…
功能:备份存储过程,视图,函数触发器,Sequence序列号等准备工作:--1.创建文件夹 :'E:/OracleBackUp/ProcBack';--文本存放的路径--2.执行:create or replace directory MyProcBakPath as 'E:/OracleBackUp/ProcBack';--3.赋权限:sqlplus /nologconn user/pswd as sysdbagrant select on DBA_OBJECTS to user;--4.创建…
环境:Oracle 11.2.0.4 DG 故障现象: 客户在备库告警日志中发现GAP sequence提示信息: Mon Nov 21 09:53:29 2016 Media Recovery Waiting for thread 1 sequence 12034 Fetching gap sequence in thread 1, gap sequence 12034-12078 Mon Nov 21 09:55:20 2016 FAL[client]: Failed to request…
The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…
Check whether the original sequence org can be uniquely reconstructed from the sequences in seqs. The org sequence is a permutation of the integers from 1 to n, with 1 ≤ n ≤ 104. Reconstruction means building a shortest common supersequence of the se…
Given a binary tree, find the length of the longest consecutive sequence path. The path refers to any sequence of nodes from some starting node to any node in the tree along the parent-child connections. The longest consecutive path need to be from p…
Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Follow up: Could you do it using only constant space complexity? 这道题让给了我们一个一维数组,让我们…
Given an unsorted array of integers, find the length of the longest consecutive elements sequence. For example, Given [100, 4, 200, 1, 3, 2], The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4. Your algorithm should run i…
The set [1,2,3,…,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…
The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…
传送门 Description Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad. Let's consider the following algorithm of generating a…
传送门 NanoApe Loves Sequence Ⅱ Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others)Total Submission(s): 1585    Accepted Submission(s): 688 Description NanoApe, the Retired Dog, has returned back to prepare for for the…
传送门 NanoApe Loves Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others) Total Submission(s): 1323    Accepted Submission(s): 521 Description NanoApe, the Retired Dog, has returned back to prepare for the Natio…
系列文章 [UML]UML系列——用例图Use Case [UML]UML系列——用例图中的各种关系(include.extend) [UML]UML系列——类图Class [UML]UML系列——类图class的关联关系(聚合.组合) [UML]UML系列——类图class的依赖关系 [UML]UML系列——类图class的泛化关系 [UML]UML系列——类图class的实现关系Realization [UML]UML系列——包图Package [UML]UML系列——活动图activity…
                                    Bracket Sequence Time Limit: 3000MS   Memory Limit: 65536KB   64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description There is a sequence of brackets, which supports two kinds of operations.1. we c…
转载链接:http://www.cnblogs.com/zhangyoushugz/archive/2012/11/09/2762720.html 众所周知,在之前的sqlserver版本中,一般采用GUID或者identity来作为标示符,但是identity是一个表对象,只能保证在一张表里面的序列,当我们遇到以下情况时, 表1 ID 订单类型 价格 1 火车票 200 4 飞机票 2000 5 船票 600 表2 ID 订单类型 价格 2 酒店 400 3 公园门票 170 6 租车费用 3…
原题连接:https://www.patest.cn/contests/pat-a-practise/1051 题目: Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, ..., N and pop randomly. You are supposed to tell if a given sequence of numbers is a possible pop seq…
Check whether the original sequence org can be uniquely reconstructed from the sequences in seqs. The org sequence is a permutation of the integers from 1 to n, with 1 ≤ n ≤ 104. Reconstruction means building a shortest common supersequence of the se…
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