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给一个sorted array 0 0 0 1 1 1 1,然后找出第一个1的位置. 边界情况:array为空或者全0. 思路:二分查找.为了优化,可以先判断最后一个数是不是0. class Solution { public: int FindBrokenCode(vector<int>& nums) { ) ; , right = nums.size() - ; while (left <= right) { ; if (!nums[mid]) left = mid + ;…
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