(动态规划)matrix -- hdu -- 5569】的更多相关文章

http://acm.hdu.edu.cn/showproblem.php?pid=5569 matrix Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 325    Accepted Submission(s): 196 Problem Description Given a matrix with n rows and m colu…
matrix Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5569 Description Given a matrix with n rows and m columns ( n+m is an odd number ), at first , you begin with the number at top-left corner (1,1) and you wa…
Problem Description Given a matrix with n rows and m columns ( n+m ,) and you want to go to the number at bottom-right corner (n,m). And you must go right or go down every steps. Let the numbers you go through become an array a1,a2,...,a2k. The cost…
简单DP /* *********************************************** Author :Zhou Zhentao Email :774388357@qq.com Created Time :2015/11/21 9:45:58 File Name :acm.cpp ************************************************ */ #include<cstdio> #include<cstring> #in…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5492 题目大意: 一个N*M的矩阵,一个人从(1,1)走到(N,M),每次只能向下或向右走.求(N+M-1)ΣN+M-1(Ai-Aavg)2最小.Aavg为平均值. (N,M<=30,矩阵里的元素0<=C<=30) 题目思路: [动态规划] 首先化简式子,得原式=(N+M-1)ΣN+M-1(Ai2)-(ΣN+M-1Ai)2 f[i][j][k]表示走到A[i][j]格子上,此时前i+j-1…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5781 题目大意: 一个人有[0,K]内随机的钱,每次可以随意取,但是不知道什么时候取完,取钱超过剩余额度会警告一次,最多警告不能超过W.求期望取出钱的次数. 题目思路: [动态规划] 二分居然错了...看来二分出的答案不一定最优..起码第三个样例过不去. f[i][j]表示钱在[0,i]区间内,警告次数不超过j的期望取钱次数.那么取一次钱k相当于把钱分成两块,[0,k]和[k+1,i],即[0,k…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5791 题目大意: A,B两个数列,问A的子集和B的子集相等的子集对数.子集内顺序按照数列顺序,相同的数字视为不同. 题目思路: [动态规划] f[i][j]表示A前i个数,B前j个数且第j个数必取的值.g[i][j]表示j不一定必取得值. ans=∑f[n][j]. // //by coolxxx //#include<bits/stdc++.h> #include<iostream>…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1081 http://acm.xmu.edu.cn/JudgeOnline/problem.php?id=1031 题目大意: 给一个n*n(n<=100)的矩阵,求一个矩形覆盖的值最大是多少. 题目思路: [动态规划] 二维的最大字段和.先考虑一维的情况.f[i]=max(f[i-1]+a[i],a[i]) 只要之前的部分和大于零则一起取一定比只取当前位置的要优. 因此只要判断局部段的和是否大于零…
Dividing Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 14861    Accepted Submission(s): 4140 Problem Description Marsha and Bill own a collection of marbles. They want to split the collection…
做水题的感觉真好系列 HDU 2084 数塔 1: 12: 1 23: 1 2 34: 1 2 3 45: 1 2 3 4 5 dp[i][j]第i行第j个数取得的最大值dp[i][j] = max(dp[i-1][j-1], dp[i-1][j]) + a[i][j]. 代码: /********************************************************* Problem : 2084 ( 数塔 ) Judge Status : Accepted RunI…