题目链接: NanoApe Loves Sequence Ⅱ Time Limit: 4000/2000 MS (Java/Others)     Memory Limit: 262144/131072 K (Java/Others) Problem Description NanoApe, the Retired Dog, has returned back to prepare for for the National Higher Education Entrance Examinatio…

题目链接:NanoApe Loves Sequence Ⅱ Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others)Total Submission(s): 339    Accepted Submission(s): 165 Problem Description NanoApe, the Retired Dog, has returned back to prepare for…

题目链接:HDU5806 题意:找出有多少个区间中第k大数不小于m. 分析:用尺取法可以搞定,CF以前有一道类似的题目. #include<cstdio> using namespace std; typedef long long ll; #define d\n I64d\n ]; ll ans; int main() { scanf("%d",&T); while (T--) { scanf("%d%d%d",&n,&m,&a…

NanoApe Loves Sequence Ⅱ Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others)Total Submission(s): 517    Accepted Submission(s): 250 Problem Description NanoApe, the Retired Dog, has returned back to prepare for for t…

分析:大于等于m的变成1,否则变成0,预处理前缀和,枚举起点,找到第一个点前缀和大于m即可 找第一个点可以二分可以尺取 #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> using namespace std; typedef long long LL; ; int T,n,m,k,a[N],sum[N]; int main(){ scanf("%d…

题目大意:给一个整数序列,统计<k,m>子序列的数目.<k,m>序列是满足第k大的数字不比m小的连续子序列. 题目分析:维护一个不小于m的数的个数的后缀和数组,可以枚举序列起点,二分查找右端点序列最近的一个<k,m>序列.因为最近右端点是不减的,所以也可以用two-pointer在O(n)的时间复杂度内得到结果. 代码如下: 使用二分查找: # include<iostream> # include<cstdio> # include<st…

传送门 NanoApe Loves Sequence Ⅱ Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others)Total Submission(s): 1585    Accepted Submission(s): 688 Description NanoApe, the Retired Dog, has returned back to prepare for for the…

传送门 NanoApe Loves Sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/131072 K (Java/Others) Total Submission(s): 1323    Accepted Submission(s): 521 Description NanoApe, the Retired Dog, has returned back to prepare for the Natio…

NanoApe Loves Sequence Ⅱ 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5806 Description NanoApe, the Retired Dog, has returned back to prepare for for the National Higher Education Entrance Examination! In math class, NanoApe picked up sequences on…

NanoApe Loves Sequence 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5805 Description NanoApe, the Retired Dog, has returned back to prepare for the National Higher Education Entrance Examination! In math class, NanoApe picked up sequences once aga…