题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=1217 题目大意 在每种钱币间进行各种交换,最后换回自己如果能赚,那么就Yes,否则No 注意应为有负权所以dijsktra在这里行不通了可以用国产的spfa算法,可比bfs. 我的AC代码 #include<iostream>#include<cstdio>#include<cstring>#include<map>#include<queue>us…

Arbitrage Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys 10.0 Frenc…

d[i]代表从起点出发可以获得最多的钱数,松弛是d[v]=r*d[u],求最长路,看有没有正环 然后这题输入有毒,千万别用cin 因为是大输入,组数比较多,然后找字符串用strcmp就好,千万不要用map 这题刚开始我T了(用的map),还以为组数很多卡spfa呢,然后我上网看了看都是floyd的,然后我用floyd写了一发,891ms过了 然后我感觉spfa的复杂度也不是很大,就是看有没有正环,所以我觉得可能是map+cin的锅,然后改了一发,用的spfa,47ms过 真是,算了,实质是本蒟蒻…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1217 题目大意:通过货币的转换,来判断是否获利,如果获利则输出Yes,否则输出No. 这里介绍一个STL中的map容器去处理数据,map<string,int>V,M; 现在我目前的理解是将字符串转换成数字,然后就是根据spfa的模板找最短路了..哇哈哈( ⊙o⊙ )哇 #include <iostream> #include <cstdio> #include <m…

Problem Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys…

hdu1217 Arbitrage Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4123    Accepted Submission(s): 1878 Problem Description Arbitrage is the use of discrepancies in currency exchange rates to tr…

描述Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys 10.0 French francs…

Description Arbitrage is the use of discrepancies in currency exchange rates to transform one unit of a currency into more than one unit of the same currency. For example, suppose that 1 US Dollar buys 0.5 British pound, 1 British pound buys 10.0 Fre…

(￣▽￣)" #include<iostream> #include<cstdio> #include<cmath> #include<algorithm> #include<cstring> #include<string> #include<vector> #include<queue> using namespace std; ; int n,m; double Vcur[MAXN],R[MAX…

汇率转换问题: 怎么样才能套利 可以用Floyd算法: #include<bits/stdc++.h> using namespace std; ][]; int main() { int n,m; map<; ,n) { string ss; ;i<=n;i++) { cin>>ss; ma[ss]=i; } string s1,s2;double rate; ;i<=n;i++) ;j<=n;j++) { ; ; } scanf("%d&quo…