66-Reorder List】的更多相关文章

[本文链接] http://www.cnblogs.com/hellogiser/p/reorder-list.html [题目] Given a singly linked list L: L0→L1→…→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example, Given {1,2,3,4,5,6,7},…
Given a singly linked list L: L0→L1→-→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→- You must do this in-place without altering the nodes' values. For example,Given {1,2,3,4}, reorder it to {1,4,2,3}. 分析: 本题可以参考reverse Linked List II的做法.这个题,依次从最后将元素放…
Given a singly linked list L: L0→L1→…→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example, Given {1,2,3,4}, reorder it to {1,4,2,3}. 这道链表重排序问题可以拆分为以下三个小问题: 1. 使用快慢指针来找到链表的中点,并将链表从中…
使用vs2012/2013配置opencv编译出现问题: 1>------ 已启动生成: 项目: Win32ForOpenCV245, 配置: Debug Win32 ------ 1>  stdafx.cpp1>  Win32ForOpenCV245.cpp1>f:\softs\opencv245\opencv\build\include\opencv2\flann\logger.h(66): error C4996: 'fopen': This function or vari…
Given a singly linked list L: L0→L1→…→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example,Given {1,2,3,4}, reorder it to {1,4,2,3}. 思路: 先把链表分成两节,后半部分翻转,然后前后交叉连接. 大神的代码比我的简洁,注意分两节时用快…
Reorder List Given a singly linked list L: L0→L1→…→Ln-1→Ln, reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example, Given {1,2,3,4}, reorder it to {1,4,2,3}. 说明:分三步,1.从中间分开,成两部分.2,后半部分链表逆置.3.插…
本问题出自:微软2014实习生及秋令营技术类职位在线测试 (Microsoft Online Test for Core Technical Positions) Description For this question, your program is required to process an input string containing only ASCII characters between '0' and '9', or between 'a' and 'z' (includi…
题目: Given a singly linked list L: L0→L1→-→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→- You must do this in-place without altering the nodes' values. For example,Given {1,2,3,4}, reorder it to {1,4,2,3}. 基本思路:     用了一个很蠢很直接的方法,定位到中间节点,后半段入栈,然后把后半段与前…
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