/* n个数有n!个排列,第k个排列,是以第(k-1)/(n-1)!个数开头的集合中第(k-1)%(n-1)!个数 */ public String getPermutation(int n, int k) { k--; List<Integer> list = new ArrayList<>(); StringBuilder res = new StringBuilder(); int count =1; //以每个数字开头的集合有多少中排列 for (int i = 2; i…

LeetCode:60. Permutation Sequence,n全排列的第k个子列 : 题目: LeetCode:60. Permutation Sequence 描述: The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order, We get the following sequence (ie, for…

LeetCode 31 Next Permutation / 60 Permutation Sequence [Permutation] <c++> LeetCode 31 Next Permutation 给出一个序列,求其下一个排列 STL中有std::next_permutation这个方法可以直接拿来用 也可以写一个实现程序: 从右往左遍历序列,找到第一个nums[i-1]<num[i]的位置,记p = i-1. 如果第一步没有找到,说明整个序列满足单调递减,也就是最大的排列,那…

The set [1,2,3,…,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…

The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order, We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "…

题目: The set [1,2,3,…,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order, We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" &q…

题目: The set [1,2,3,…,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order, We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" &q…

一天一道LeetCode系列 (一)题目 The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order, We get the following sequence (ie, for n = 3): 1:"123" 2:"132"  3 : "213" 4 :&quo…

题目 The set [1,2,3,-,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order, We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" &qu…

The set [1,2,3,…,n] contains a total of n! unique permutations. By listing and labeling all of the permutations in order,We get the following sequence (ie, for n = 3): "123" "132" "213" "231" "312" "3…