Backward Digit Sums Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5664   Accepted: 3280 Description FJ and his cows enjoy playing a mental game. They write down the numbers from 1 to N (1 <= N <= 10) in a certain order and then sum ad…

1653: [Usaco2006 Feb]Backward Digit Sums Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 207  Solved: 161[Submit][Status][Discuss] Description FJ and his cows enjoy playing a mental game. They write down the numbers from 1 to N (1 <= N <= 10) in a cer…

Backward Digit Sums Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 5495   Accepted: 3184 Description FJ and his cows enjoy playing a mental game. They write down the numbers from 1 to N (1 <= N <= 10) in a certain order and then sum ad…

1653: [Usaco2006 Feb]Backward Digit Sums Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 285  Solved: 215[Submit][Status] Description FJ and his cows enjoy playing a mental game. They write down the numbers from 1 to N (1 <= N <= 10) in a certain orde…

Backward Digit Sums Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4487   Accepted: 2575 Description FJ and his cows enjoy playing a mental game. They write down the numbers from 1 to N (1 <= N <= 10) in a certain order and then sum ad…

POJ 3187  Backward Digit Sums http://poj.org/problem?id=3187 题目大意: 给你一个原始的数字序列: 3   1   2   4  他可以相邻的元素相加得到 4 3 6 然后 7 9 最后得到16,现在给定序列的长度,还有最后的得数,求原始序列(多解则取最小) 思路: 直接枚举即可. 下面是next_permutation版本. #include<cstdio> #include<cstdlib> #include<c…

-->Backward Digit Sums 直接写中文了 Descriptions: FJ 和 他的奶牛们在玩一个心理游戏.他们以某种方式写下1至N的数字(1<=N<=10). 然后把相邻的数相加的到新的一行数.重复这一操作直至只剩一个数字.比如下面是N=4时的一种例子 3 1 2 4 4 3 6 7 9 16 在FJ回来之前,奶牛们开始了一个更难的游戏:他们尝试根据最后结果找到开始的序列.这已超过了FJ的思考极限. 写一个程序来帮助FJ吧 Input N和最后的和 Output 满足…

P1118 [USACO06FEB]Backward Digit Sums G/S 题解:  (1)暴力法.对1-N这N个数做从小到大的全排列,对每个全排列进行三角形的计算,判断是否等于N.  对每个排列进行三角形计算,需要O(N2)次.例如第1行有5个数{a,b,c,d,e},那么第2行计算4次,第3行计算3次-等等,总次数是O(N2)的.  a    b    c    d    e    a+b    b+c   c+d   d+e      a+2b+c b+2c+d c+2d+e   …

http://poj.org/problem?id=3187 给定一个个数n和sum,让你求原始序列,如果有多个输出字典序最小的. 暴力枚举题,枚举生成的每一个全排列,符合即退出. dfs版: #include <iostream> #include <cstdio> #include <cmath> #include <vector> #include <cstring> #include <string> #include <…

http://www.lydsy.com/JudgeOnline/problem.php?id=1653 看了题解才会的..T_T 我们直接枚举每一种情况(这里用next_permutation,全排列) 然后判断是否符合情况(累加判断) #include <cstdio> #include <cstring> #include <cmath> #include <string> #include <iostream> #include <…