Reverse a singly linked list. 做II之前应该先来做1的,这个倒是很简单,基本上不用考虑什么,简单的链表反转而已: /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* rev…