此题无法用JavaAC,不相信的可以去HD1029题试下! Problem Description "OK, you are not too bad, em- But you can never pass the next test." feng5166 says. "I will tell you an odd number N, and then N integers. There will be a special integer among them, you hav…

Ignatius and the Princess IV hdoj-1029 这里主要是先排序,因为要找出现了一半以上的数字,所以出现的数字一定在中间 方法一: #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<cmath> using namespace std; int n; int a[10000007]; int main(…

HDOJ 1501 Zipper [简单DP] Problem Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arbitrarily, but each must stay in i…

D. Fedor and Essay time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output After you had helped Fedor to find friends in the «Call of Soldiers 3» game, he stopped studying completely. Today, the E…

这一次组织了一场\(dp\)的专项考试,出了好几道经典的简单\(dp\)套路题,特开一篇博客写一下题解. Tower(双向dp) Description 信大家都写过数字三角形问题,题目很简单求最大化一个三角形数塔从上往下走的路径和.走的规则是:(i,j)号点只能走向(i+1,j)或者(i+1,j+1).如下图是一个数塔,映射到该数塔上行走的规则为:从左上角的点开始,向下走或向右下走直到最底层结束. 1 3 8 2 5 0 1 4 3 8 1 4 2 5 0 路径最大和是1+8+5+4+4 =…

题目链接:  http://poj.org/problem?id=1088 题目要求: 一个人可以从某个点滑向上下左右相邻四个点之一,当且仅当高度减小.求可以滑落的最长长度. 题目解析: 首先要先排一下序,因为只能高度递减才能滑行.之后就很简单了,就是简单DP. 即:要求的滑坡是一条节点递减并依次相邻的最长路径,可以先根据高度将所有的点进行排序,在i点的时候,遍历0~i-1个点(升序排序,i前面的点的高度一定小于等于i),取相邻点间的大的路径长度 代码如下: #include <iostream…

Kattis - bank [简单DP] Description Oliver is a manager of a bank near KTH and wants to close soon. There are many people standing in the queue wanting to put cash into their accounts after they heard that the bank increased the interest rates by 42% (f…

http://acm.timus.ru/problem.aspx?space=1&num=1203 按照结束时间为主,开始时间为辅排序,那么对于任意结束时间t,在此之前结束的任务都已经被处理,从这个时间开始的任务都正要被处理, 因为t<=3e5,可以用简单dp解决 #include <cstdio> #include <algorithm> using namespace std; const int maxn=1e5+5; int n; typedef pair&l…

/* 简单dp,要记录顺序 解:先排序,然后是一个最长下降子序列 ,中间需记录顺序 dp[i]=Max(dp[i],dp[j]+1); */ #include<stdio.h> #include<string.h> #include<stdlib.h> #define N 1100 /*w,s代表重量和速度,index记录原来输入时的顺序下标,pre指向排序后的上一个下标,answer记录排序后每一个位置的最优值*/ typedef struct node { int…

免费馅饼 Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 102   Accepted Submission(s) : 35 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description 都说天上不会掉馅饼,但有一天gameboy正走在回家的小径上,…