Partition List Total Accepted: 19761 Total Submissions: 73252My Submissions Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order…

LeetCode: Palindrome Partition Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab", Return [ ["aa","b"], [&q…

刷完了LeetCode链表相关的经典题目,总结一下用到的技巧: 技巧 哑节点--哑节点可以将很多特殊case(比如:NULL或者单节点问题)转化为一般case进行统一处理,这样代码实现更加简洁,优雅 两个指针--链表相关的题目一般都需要用到两个指针:prev指针和cur指针 头插法--主要用于reverse链表 前后指针/slow fast指针--用于检测链表是否存在环…

Leetcode链表 一.闲聊 边学边刷的--慢慢写慢慢更 二.题目 1.移除链表元素 题干: 思路: 删除链表节点,就多了一个判断等值. 由于是单向链表,所以要删除节点时要找到目标节点的上一个节点,如果是双向链表,指向要删除节点本身即可 链表的头节点存在着被删除的风险,所以使用虚拟头节点来方便返回 代码: public class ListNode{ int val; ListNode next; ListNode() {} ListNode(int val) {this.val=val;}…

Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. Example: Input: head = 1->4->3-…

86. 分隔链表 86. Partition List 题目描述 给定一个链表和一个特定值 x,对链表进行分隔,使得所有小于 x 的节点都在大于或等于 x 的节点之前. 你应当保留两个分区中每个节点的初始相对位置. LeetCode86. Partition List中等 示例: 输入: head = 1->4->3->2->5->2, x = 3 输出: 1->2->2->4->3->5 Java 实现 ListNode Class publi…

Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. Example: Input: head = 1->4->3-…

Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. Input: head = 1->4->3->2->…

[题目] Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. For example,Given 1->4->3-…

/* 这个题是medium的意思应该是用双指针的方法做,如果使用下边的新建链表的方法,就是easy的题目了 双指针会用到很多链表的相连操作 */ public ListNode partition(ListNode head, int x) { ListNode s = null; ListNode b = null; ListNode temp=null,res=null; while (head!=null) { int cur = head.val; if (head.val<x) { i…