Hat's Words Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9574    Accepted Submission(s): 3421 Problem Description A hat's word is a word in the dictionary that is the concatenation of exactl…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1247 Problem DescriptionA hat’s word is a word in the dictionary that is the concatenation of exactly two other words in the dictionary.You are to find all the hat’s words in a dictionary. InputStandard…

Problem Description A hat's word is a word in the dictionary that is the concatenation of exactly two other words in the dictionary. You are to find all the hat's words in a dictionary.   Input Standard input consists of a number of lowercase words,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1247 思路分析:题目要求找出在输入字符串中的满足要求(该字符串由输入的字符串中的两个字符串拼接而成)的字符串. 对于长度为LEN的字符串,其可能由LEN种可能的拼接可能:现在问题转化为查找能够拼接成该字符串的可能的两个字符串是否都在 输入的字符串中,使用字典树可以实现快速的字符串查找,算法复杂度为O(N*M),N为输入字符串的个数,M为字符串长度. 代码如下: #include <cstdio>…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1247 题目大意: 给出一些单词,以EOF结束,看其中哪一个单词可以由其他两个单词组成,将其输出 解题思路: 将所有单词存入字典树中,每个单词拆成两部分查询是不是字典树中的单词. 此处是查询是不是单词,需要加单词标记数组,在每个单词最后一位的末尾那个节点标记true 传送门:字典树模板 #include<iostream> #include<cstdio> #include<cs…

题目大意 给定一些单词,要求你把所有的帽子单词找出来,如果某个单词恰好由另外两个单词连接而成,那么它就是帽子单词 题解 先把所有单词插入到Trie树,然后判断每个单词是不是帽子单词,做法就是:对于第i个单词,假设为s[0..n],枚举中间节点j,在Trie树上查询s[0..j]和s[j+1,-n]两个单词是否存在,存在的话说明它就是帽子词-WA了几发,找到帽子单词的时候忘记break了... 代码: #include <iostream> #include <cstdio> #in…

Hat's Words 题意:给出一张单词表求有多少个单词是由单词表里的两个单词组成,可以重复!按字典序输出这些单词. 思路:先建一个字典树,然后枚举每个单词,把每个单词任意拆分两部分然后查找. 目测数据不强,开始不知道单词长度都不敢下手了.. struct tree { bool f; tree *next[N]; tree() { for(int i=0;i<N;i++) next[i]=NULL; f=false; } }; void insert(tree *root,char *s)…

Hat's Words(hdu1247) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 6156 Accepted Submission(s): 2289 Problem Description A hat's word is a word in the dictionary that is the concatenation of exa…

Hat’s Words Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7282    Accepted Submission(s): 2639 Problem Description A hat’s word is a word in the dictionary that is the concatenation of exactly…

题意:给一个字符串集,要你给出n个字符串s,使s能被所给字符串集中的两个相加所得(ahat=a+hat) 思路:简单字典树题,注意查询的时候要判断所指next是否为NULL,否则会RE非法访问. 代价: #include<cstdio> #include<cstring> #include<cstdlib> #include<queue> #include<cmath> #include<string> #include<sta…