一本通1640C Looooops

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一本通1640C Looooops

1640:C Looooops 时间限制: 1000 ms 内存限制: 524288 KB [题目描述] 原题来自:CTU Open 2004 对于 C 语言的 for (variable = A; variable != B; variable += C) statement; 循环语句,问在 k 位存储系统中循环几次才会结束.若在有限次内结束,则输出循环次数.否则输出死循环. [输入] 多组数据,每组数据一行四个整数 A,B,C,k.k 表示 k 位存储系统. 读入以0 0…

POJ2115 C Looooops[扩展欧几里得]

C Looooops Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 24355 Accepted: 6788 Description A Compiler Mystery: We are given a C-language style for loop of type for (variable = A; variable != B; variable += C) statement; I.e., a loop w…

POJ 2115 C Looooops

扩展GCD...一定要(1L<<k),不然k=31是会出错的 .... C Looooops Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 15444 Accepted: 3941 Description A Compiler Mystery: We are given a C-language style for loop of type for (variable…

poj 2115 Looooops

C Looooops Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 23637 Accepted: 6528 Description A Compiler Mystery: We are given a C-language style for loop of type for (variable = A; variable != B; variable += C) statement; I.e., a loop w…

C Looooops(扩展欧几里得)

C Looooops Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 20128 Accepted: 5405 Description A Compiler Mystery: We are given a C-language style for loop of type for (variable = A; variable != B; variable += C) statement; I.e., a loop which…

POJ2115——C Looooops(扩展欧几里德+求解模线性方程)

C Looooops DescriptionA Compiler Mystery: We are given a C-language style for loop of type for (variable = A; variable != B; variable += C) statement;I.e., a loop which starts by setting variable to value A and while variable is not equal to B, repea…

Poj 2115 C Looooops(exgcd变式)

C Looooops Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 22704 Accepted: 6251 Description A Compiler Mystery: We are given a C-language style for loop of type for (variable = A; variable != B; variable += C) statement; I.e., a loop which…