1410 - Consistent Verdicts   PDF (English) Statistics Forum Time Limit: 5 second(s) Memory Limit: 32 MB In a 2D plane N persons are standing and each of them has a gun in his hand. The plane is so big that the persons can be considered as points and…

链接: https://vjudge.net/problem/LightOJ-1410 题意: In a 2D plane N persons are standing and each of them has a gun in his hand. The plane is so big that the persons can be considered as points and their locations are given as Cartesian coordinates. Each…

题目链接:https://vjudge.net/contest/28079#problem/Q 题目大意:题目描述很长很吓人,大概的意思就是有n个坐标代表n个人的位置,每个人听力都是一样的,每人发出一枪,然后每个人给出一个数字表示听到的枪响次数,汇总为结果,结果有很多种(因为不知道人的听力极限范围),问有几种一致的结果(每个人的答案都是不矛盾的). 解题思路:就是判断一下人和人之间的距离有多少种+1,直接计算所有人之间距离排序去重+1就好了. 代码: #include<iostream> #i…

Consistent Verdicts Time Limit: 5000MS   Memory Limit: 32768KB   64bit IO Format: %lld & %llu Submit Status Description In a 2D plane N persons are standing and each of them has a gun in his hand. The plane is so big that the persons can be considere…

在10g中,Oracle推出了自己的SQL优化辅助工具: SQL优化器(SQL Tuning Advisor :STA),它是新的DBMS_SQLTUNE包. 使用STA一定要保证优化器是CBO模式下.可是我觉得使用这样的工具,仅适合全然不懂SQL的调优的人群,不要觉得工具能解决好问题. SQL说究竟是表达的是一个业务,工具怎么可能理解业务.SQL调优还是要用autotrace,10046,10053,display_cursor这些优秀的工具做诊断.然后依据业务和所具备的oracle基础的知识…

摘要: 本文首先以一个经典的分布式缓存的应用场景为铺垫,在了解了这个应用场景之后,生动而又不失风趣地介绍了一致性哈希算法,同时也明确给出了一致性哈希算法的优点.存在的问题及其解决办法. 声明与致谢: 本文转载于朱双印博主的个人日志<白话解析:一致性哈希算法 consistent hashing>一文. 一. 引子 在了解一致性哈希算法之前,最好先了解一下缓存中的一个应用场景,了解了这个应用场景之后,再来理解一致性哈希算法,就容易多了,也更能体现出一致性哈希算法的优点,那么,我们先来描述一下这个…

Problem description: To brighten up the gala dinner of the IOI'98 we have a set of N coloured lamps numbered from 1 to N. The lamps are connected to four buttons: button 1 -- when this button is pressed, all the lamps change their state: those that a…

如何在ASP.NET Web站点中统一页面布局[Creating a Consistent Layout in ASP.NET Web Pages(Razor) Sites] 一.布局页面介绍[About Layout Pages] 很多网站有些内容需要显示在各个页面中,比如Header,Footer或者告诉用户已经登录的部分.ASP.NET允许你创建一个单独的文件来包含文本.标签和代码的内容块,从而搭建一个风格整齐的网站.接下来你就可以将这个内容块插入到任何你想要让它展示的页面中.采用这种方法…

Happy 2004 题意:s为2004^x的因子和,求s%29.     (题于文末) 知识点: 素因子分解:n = p1 ^ e1 * p2 ^ e2 *..........*pn ^ en 因子和:    Sum=(p1^0+p1^1-.p1^e1)*(p2^0+p2^1-p2^e2)--(pn^0+-pn^en) =; 积性函数:s(xy)=s(x)*s(y)    (比如:幂函数,因子和,欧拉函数,莫比乌斯函数) 对于正整数n的一个算术函数 f(n),若f(1)=1,且当a,b互质时f…

传送门 Description Chloe, the same as Vladik, is a competitive programmer. She didn't have any problems to get to the olympiad like Vladik, but she was confused by the task proposed on the olympiad. Let's consider the following algorithm of generating a…