Bone Collector II(HDU 2639 DP)】的更多相关文章

Bone Collector II Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3471    Accepted Submission(s): 1792 Problem Description The title of this problem is familiar,isn't it?yeah,if you had took par…
http://acm.hdu.edu.cn/showproblem.php?pid=2639       Problem Description The title of this problem is familiar,isn't it?yeah,if you had took part in the "Rookie Cup" competition,you must have seem this title.If you haven't seen it before,it does…
题意:求01背包的第k最优值 输入:第一行为T,下面是T组数据,每组数据有n,m,k 代表n件物品,m容量,和题目要求的k,下一行是n个物品的价值,再一行是n个物品的体积 输出:T行答案 /* 类似于归并排序中合并的做法,对于f[i][j]的k个最优值,从f[i-1][j]和f[i-1][j-w[i]]+v[i] 的k个最优值中选出最优的k个放入 */ #include<cstdio> #include<iostream> #include<cstring> #defi…
The title of this problem is familiar,isn't it?yeah,if you had took part in the "Rookie Cup" competition,you must have seem this title.If you haven't seen it before,it doesn't matter,I will give you a link: Here is the link: http://acm.hdu.edu.c…
Bone Collector II Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3355    Accepted Submission(s): 1726 Problem Description The title of this problem is familiar,isn't it?yeah,if you had took par…
Bone Collector II Time Limit: 5000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 4178    Accepted Submission(s): 2174 Problem Description The title of this problem is familiar,isn't it?yeah,if you had took pa…
01背包,求第k大. 以前看k短路的时候看过代码以为懂了 = =结果还是跑去看了别人的代码才会.果然要自己写一遍才行啊 0.0难得1A.. 每次把可能的2k种求出来,求前k个.注意要不一样的k个数.. /************************************************************** Problem : 2639 ( Bone Collector II ) Judge Status : Accepted RunId : 15212165 Languag…
题目链接 Problem Description The title of this problem is familiar,isn't it?yeah,if you had took part in the "Rookie Cup" competition,you must have seem this title.If you haven't seen it before,it doesn't matter,I will give you a link: Here is the l…
这题和典型的01背包求最优解不同,是要求第k优解,所以,最直观的想法就是在01背包的基础上再增加一维表示第k大时的价值.具体思路见下面的参考链接,说的很详细 参考连接:http://laiba2004.blog.163.com/blog/static/8835120220138611342496/http://hi.baidu.com/chenyun00/item/1c6c44318acc8bfaa88428c7 #include <iostream> #include <cstdio&…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2639 题意:求01背包的第k优解 dp(i, j)表示容量为j时的i优解 对于第二维的操作和01背包几乎一样,只是我们只需要关注每一次取的前k大个即可. #include <algorithm> #include <iostream> #include <iomanip> #include <cstring> #include <climits> #…