题意:http://acdream.info/problem?pid=1112 Problem Description Here is Alice and Bob again ! Alice and Bob are playing a game. There are several numbers.First, Alice choose a number n.Then he can replace n (n > 1)with one of its positive factor but not…
option=com_onlinejudge&Itemid=8&page=show_problem&problem=4246" target="_blank" style="">题目连接:uva 1500 - Alice and Bob 题目大意:在黑板上又一个序列,每次操作能够选择一个数减1,或者是合并两个数,一个数被减至1则自己主动消除,不能操作者输. 解题思路:结论,对于大于1的数能够看成是一个整数s,为消除他们的总操作…
又见Alice and Bob 时间限制:1000 ms | 内存限制:65535 KB 难度:3 描述 集训生活如此乏味,于是Alice和Bob发明了一个新游戏.规则如下:首先,他们得到一个集合包含n个特定的整数,接着他们轮流做以下操作,每一次操作,Alice或者Bob(轮到谁就是谁)会从集合中选择两个整数x 和 y ,(但是集合中不能包含| x - y|),接着他就会把整数|x - y| 加入集合,因此,集合中的数据多加了一个…… 如果当前玩家不能执行操作了,他就输了.问题是如果Al…
Alice and Bob Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 147 Accepted Submission(s): 22 Problem Description As you know, Alice and Bob always play game together, and today they get a…
Alice and Bob Time Limit: 1000ms Memory limit: 65536K 题目描述 Alice and Bob like playing games very much.Today, they introduce a new game. There is a polynomial like this: (a0*x^(2^0)+1) * (a1 * x^(2^1)+1)*.......*(an-1 * x^(2^(n-1))+1). Then Alice as…
http://acm.sdut.edu.cn/sdutoj/problem.php?action=showproblem&problemid=2608 Alice and Bob Time Limit: 1000ms Memory limit: 65536K 有疑问?点这里^_^ 题目描述 Alice and Bob like playing games very much.Today, they introduce a new game. There is a polynomial li…
Alice and Bob Time Limit : 10000/5000ms (Java/Other) Memory Limit : 32768/32768K (Java/Other) Total Submission(s) : 5 Accepted Submission(s) : 1 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Alice and Bob's game nev…