lc132 Palindrome Pairs 2 大致与lc131相同,这里要求的是最小分割方案 同样可以分割成子问题 dp[i][j]还是表示s(i~j)是否为palindrome res[i]则用来记录s(0~i)的最小cut数 class Solution { public int minCut(String s) { int[] dp = new int[s.length()]; boolean[][] isP = new boolean[s.length()][s.length()];…

原题链接在这里:https://leetcode.com/problems/palindrome-pairs/ 题目: Given a list of unique words, find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1:Giv…

lc131 Palindrome Pairs 解法1: 递归 观察题目,要求,将原字符串拆成若干子串,且这些子串本身都为Palindrome 那么挑选cut的位置就很有意思,后一次cut可以建立在前一次cut的基础上 举例来说 "aab" 第一次cut"a" "ab" 第二次cut"a" "b" 很容易总结出规律,s(i, j)被i=<k<j,截断 若s(i,k)本身就是palindrome,那…

https://leetcode.com/problems/palindrome-pairs/ Given a list of unique words. Find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1: Given words =…

1. Description Given a list of unique words. Find all pairs of distinct indices (i, j) in the given list, so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1: Given words = ["bat", "tab", &qu…

Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab",Return 1 since the palindrome partitioning ["aa",…

Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. Example: Input: "aab" Output: 1 Explanation: The palindrome partitioning ["aa"…

Given a string s, partition s such that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. For example, given s = "aab", Return 1 since the palindrome partitioning ["aa"…

求次数的问题一般用DP class Solution(object): def minCut(self, s): """ :type s: str :rtype: int """ n = len(s) maxInt = 2147483647 cuts = [maxInt for x in range(n)] p = self.palinTable(s) for i in range(n): temp = maxInt if p[0][i] ==…

https://leetcode.com/problems/palindrome-partitioning/ Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s = "aab",Return [ ["aa&qu…