Cache容量计算例题: 假定主存地址位数为32位,按字节编址,主存和cache之间采用4-路组相联映射方式,主存块大小为4个字,每字32位,采用直写(Write Throght)方式和LRU替换策略,则能存放32K字数据的cache的总容量至少应有( )位. 得分/总分 A. 4672K B. 1168K C. 1184K D. 4736K 正确答案:C 解析: C.cache共有32K字/4字=8K行,因为采用4-路组相联,因而共有8K/4=2K组,组号占11位:每个主存块为4字=4×32位…
About Searching The Search API allows you to execute arbitrarily complex queries against caches. The development of alternative indexes on values provides the ability for data to be looked up based on multiple criteria instead of just keys. Note: Ter…
每每勤勤恳恳,思来想去,趁还有激情,先把它记录下来... 定义一个Stu的类: public class Stu { public string Name { get; set; } public int Age { get; set; } } 使用Stu类创建一个类实例变量stu,并把stu保存到缓存中 if ((Stu)HttpRuntime.Cache["myStu"] == null) { Stu stu= new Stu(){Name="yshuangj"…
free命令可选参数 -b,-k,-m,-g show output in bytes, KB, MB, or GB -h human readable output (automatic unit scaling) -l show detailed low and high memory statistics -o use old format (no -/+buffers/cache line) -t display total for RAM + swap -s update every…
1.java计算公式 @Override public int hashCode() { //设置初始值 ; //假设有效域为: name,age,idCardNo,incomeAnnual,sex,brithDay ; //计算name (String为对象类型,他的计算直接调用本身的hashCode) c = name.hashCode(); result = result * + c; //计算age (int/byte/char/short类型,他的计算直接调用本身的值) c = thi…
