Wavio Sequence  Wavio is a sequence of integers. It has some interesting properties. ·  Wavio is of odd length i.e. L = 2*n + 1. ·  The first (n+1) integers of Wavio sequence makes a strictly increasing sequence. ·  The last (n+1) integers of Wavio s…

题目传送门 题意:找对称的,形如:123454321 子序列的最长长度 分析:LIS的nlogn的做法,首先从前扫到尾,记录每个位置的最长上升子序列,从后扫到头同理.因为是对称的,所以取较小值*2-1再取最大值 代码: /************************************************ * Author :Running_Time * Created Time :2015-8-5 21:38:32 * File Name :UVA_10534.cpp ******…

// uva 10534 Wavio Sequence // // 能够将题目转化为经典的LIS. // 从左往右LIS记作d[i],从右往左LIS记作p[i]; // 则最后当中的min(d[i],p[i])就是这个波动序列的一半 // 在这最后的min(d[i],p[i]) * 2 + 1 的最大值就是我们所要求的答案 // // 这题開始想的最后的答案是d[i]==p[i]的时候求最大. // 可是这样是不正确的,比如n=4, // 1,3,1,0 // 最长的应该是3,可是我的答案是1,…

题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=68553#problem/B 题目要求: Wavio是一个整数序列,具有以下特性: 1.Wavio序列的长度是奇数, 即 L = 2 * n + 1; 2.Wavio序列前 n+1 个整数是递增序列 3.Wavio序列后 n+1 个整数是递减序列 如示例 1 2 3 4 5 4 3 2 1 10 最长的 Wavio序列 为 1 2 3 4 5 4 3 2 1 ,所以答案为9 题…

题目链接:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=17&page=show_problem&problem=1475 Dynamic Programming. 最长增长子序列.推荐一个链接:http://www.cnblogs.com/liyukuneed/archive/2013/05/26/3090402.html.按照链接里的方法三(其他的会有TLE…

Longest Ordered Subsequence Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 41944   Accepted: 18453 Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ...…

题意:给定一个序列,求一个最长子序列,使得序列长度为奇数,并且前一半严格递增,后一半严格递减. 析:先正向和逆向分别求一次LIS,然后再枚举中间的那个数,找得最长的那个序列. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath>…

Longest Increasing Subsequence The longest increasing subsequence problem is to find a subsequence of a given sequence in which the subsequence's elements are in sorted order, lowest to highest, and in which the subsequence is as long as possible. Th…

Wavio Sequence My Tags (Edit) Source : UVA Time limit : 1 sec Memory limit : 32 M Submitted : 296, Accepted : 123 Wavio is a sequence of integers. It has some interesting properties. Wavio is of odd length i.e. L = 2 * n + 1. The first (n+1) integers…

大意是有一些n维的物体,他的边也是n条,如果将一个物体的边按任意顺序排列,只要有一种排列满足一一对应小于另一物体的边,就可以将这个物体嵌套进去另一个物体中,文最多能连续嵌套几个物体. 所求的最多的连续嵌套数与最长递增子序列相似,只不过一般的是单个数的比较,这里是一列数的比较.还有就是满足条件的嵌套的物体的编号用递归来求. 还可以记忆化搜索. #include<cstdio> #include<cstring> #include<iostream> #include<…